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A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.?
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Solution:
Given,
Initial velocity, u = 0
Distance covered in 5 seconds, s1 = 25 cm
Distance covered in 7 seconds, s2 = 33 cm
We need to find the velocity at the end of 9 seconds, i.e. v9.
Using the equations of motion:
We know that,
s = ut + (1/2)at^2
where,
s is the distance covered
u is the initial velocity
t is the time taken
a is the acceleration
Calculating acceleration:
Acceleration can be calculated using the following formula:
a = (s2 - s1) / (t2^2 - t1^2)
where,
t1 = 5 seconds
t2 = 7 seconds
Substituting the given values, we get:
a = (33 - 25) / (7^2 - 5^2)
a = 4 cm/s^2
Calculating velocity at the end of 9 seconds:
Using the equation of motion:
v = u + at
where,
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
Substituting the given values, we get:
v9 = 0 + (4 cm/s^2) x 9 seconds
v9 = 36 cm/s
Therefore, the velocity of the body at the end of 9 seconds from start is 36 cm/s.
Given,
Initial velocity, u = 0
Distance covered in 5 seconds, s1 = 25 cm
Distance covered in 7 seconds, s2 = 33 cm
We need to find the velocity at the end of 9 seconds, i.e. v9.
Using the equations of motion:
We know that,
s = ut + (1/2)at^2
where,
s is the distance covered
u is the initial velocity
t is the time taken
a is the acceleration
Calculating acceleration:
Acceleration can be calculated using the following formula:
a = (s2 - s1) / (t2^2 - t1^2)
where,
t1 = 5 seconds
t2 = 7 seconds
Substituting the given values, we get:
a = (33 - 25) / (7^2 - 5^2)
a = 4 cm/s^2
Calculating velocity at the end of 9 seconds:
Using the equation of motion:
v = u + at
where,
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
Substituting the given values, we get:
v9 = 0 + (4 cm/s^2) x 9 seconds
v9 = 36 cm/s
Therefore, the velocity of the body at the end of 9 seconds from start is 36 cm/s.
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A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.?
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A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.?.
A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving with uniform acceleration covers 25cm and 33cm in fifth and seventh seconds respectively. Find it's velocity at the end of 9th second from start.?.
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