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2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ?
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2kg of air is heated at constant volume.The temperature of air is incr...
To calculate the amount of heat absorbed by the air, we will use the equation:
Q = m * C * ΔT
Where:
Q = Amount of heat absorbed
m = Mass of the air (2 kg)
C = Specific heat of air at constant volume (0.718 kJ/kgK)
ΔT = Change in temperature (313 K - 293 K = 20 K)
Now, let's calculate the amount of heat absorbed:
Q = 2 kg * 0.718 kJ/kgK * 20 K
Q = 28.72 kJ
Therefore, the amount of heat absorbed by the air is 28.72 kJ.
Explanation:
- We are given the mass of the air (2 kg) and the change in temperature (20 K).
- The specific heat of air at constant volume (C) is also given as 0.718 kJ/kgK.
- We use the equation Q = m * C * ΔT to calculate the amount of heat absorbed.
- Substituting the given values, we find that the heat absorbed is 28.72 kJ.
Q = m * C * ΔT
Where:
Q = Amount of heat absorbed
m = Mass of the air (2 kg)
C = Specific heat of air at constant volume (0.718 kJ/kgK)
ΔT = Change in temperature (313 K - 293 K = 20 K)
Now, let's calculate the amount of heat absorbed:
Q = 2 kg * 0.718 kJ/kgK * 20 K
Q = 28.72 kJ
Therefore, the amount of heat absorbed by the air is 28.72 kJ.
Explanation:
- We are given the mass of the air (2 kg) and the change in temperature (20 K).
- The specific heat of air at constant volume (C) is also given as 0.718 kJ/kgK.
- We use the equation Q = m * C * ΔT to calculate the amount of heat absorbed.
- Substituting the given values, we find that the heat absorbed is 28.72 kJ.
Community Answer
2kg of air is heated at constant volume.The temperature of air is incr...
6.838
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2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ?
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2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ?.
2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2kg of air is heated at constant volume.The temperature of air is increased from 293K to 313K.If the specific healt of air at constant leletwo is 0.718kJ/kgK the amount of heat absorbed U(1)=4.2/kcal 257.8kJ .3514.68kJ 1) 6.838kJ 4) 28.72kJ?.
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