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A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B−→, such that B−→ is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]
- a)irB→
- b)2πriB→
- c)Zero
- d)πriB→
Correct answer is option 'C'. Can you explain this answer?
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A conducting circular loop of radius r carries a constant current i. I...
Net force on a current carrying closed loop is always zero, if it is placed in an uniform magnetic field.
Most Upvoted Answer
A conducting circular loop of radius r carries a constant current i. I...
The loop will experience a torque due to the magnetic field. The torque can be calculated using the formula:
τ = NIABsinθ
Where:
τ = torque
N = number of turns in the loop
I = current flowing through the loop
A = area of the loop
B = magnetic field
θ = angle between the magnetic field and the normal to the loop
Since the loop is circular, the area can be calculated as:
A = πr^2
The torque can be written as:
τ = (NIABsinθ)
Since the current is constant and the loop is circular, the torque can be simplified as:
τ = (IA)Bsinθ
Now, if the magnetic field is perpendicular to the plane of the loop (θ = 90°), the torque can be further simplified as:
τ = (IA)B
So, in summary, when a conducting circular loop of radius r carries a constant current i and is placed in a uniform magnetic field B, it will experience a torque given by τ = (IA)B.
τ = NIABsinθ
Where:
τ = torque
N = number of turns in the loop
I = current flowing through the loop
A = area of the loop
B = magnetic field
θ = angle between the magnetic field and the normal to the loop
Since the loop is circular, the area can be calculated as:
A = πr^2
The torque can be written as:
τ = (NIABsinθ)
Since the current is constant and the loop is circular, the torque can be simplified as:
τ = (IA)Bsinθ
Now, if the magnetic field is perpendicular to the plane of the loop (θ = 90°), the torque can be further simplified as:
τ = (IA)B
So, in summary, when a conducting circular loop of radius r carries a constant current i and is placed in a uniform magnetic field B, it will experience a torque given by τ = (IA)B.
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A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic fieldB−→, such thatB−→is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]a)irB→b)2πriB→c)Zerod)πriB→Correct answer is option 'C'. Can you explain this answer?
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