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A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B−→, such that B−→ is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]
  • a)
     irB→
  • b)
     2πriB→
  • c)
     Zero
  • d)
     πriB→
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A conducting circular loop of radius r carries a constant current i. I...
Net force on a current carrying closed loop is always zero, if it is placed in an uniform magnetic field.
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Most Upvoted Answer
A conducting circular loop of radius r carries a constant current i. I...
The loop will experience a torque due to the magnetic field. The torque can be calculated using the formula:

τ = NIABsinθ

Where:
τ = torque
N = number of turns in the loop
I = current flowing through the loop
A = area of the loop
B = magnetic field
θ = angle between the magnetic field and the normal to the loop

Since the loop is circular, the area can be calculated as:

A = πr^2

The torque can be written as:

τ = (NIABsinθ)

Since the current is constant and the loop is circular, the torque can be simplified as:

τ = (IA)Bsinθ

Now, if the magnetic field is perpendicular to the plane of the loop (θ = 90°), the torque can be further simplified as:

τ = (IA)B

So, in summary, when a conducting circular loop of radius r carries a constant current i and is placed in a uniform magnetic field B, it will experience a torque given by τ = (IA)B.
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A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic fieldB−→, such thatB−→is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]a)irB→b)2πriB→c)Zerod)πriB→Correct answer is option 'C'. Can you explain this answer?
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A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic fieldB−→, such thatB−→is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]a)irB→b)2πriB→c)Zerod)πriB→Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic fieldB−→, such thatB−→is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]a)irB→b)2πriB→c)Zerod)πriB→Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic fieldB−→, such thatB−→is perpendicular to the plane of the loop. The magnetic force acting on the loop is [BIT 1992; MP PET 1994; IIT 1983; MP PMT 1999; AMU (Engg.) 2000]a)irB→b)2πriB→c)Zerod)πriB→Correct answer is option 'C'. Can you explain this answer?.
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