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Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic mean of the remaining numbers is 105/4. Find n and those removed numbers?
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Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic ...
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Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic ...
Given information:
- Two consecutive numbers are removed from the list 1, 2, 3, ..., n.
- The arithmetic mean of the remaining numbers is 105/4.

Approach:
1. Let's assume the two consecutive numbers that are removed are x and x+1.
2. We need to find the value of n and the removed numbers x and x+1.

Solution:

Step 1: Find the arithmetic mean of the remaining numbers:
1. The sum of the numbers from 1 to n (inclusive) can be calculated using the formula: sum = (n/2)(first term + last term).
2. The first term in the given list is 1, and the last term is n.
3. So, the sum of the numbers from 1 to n is (n/2)(1 + n).

Step 2: Calculate the sum of the remaining numbers:
1. Since we removed two numbers, the sum of the remaining numbers will be reduced by (x + x+1).
2. The sum of the remaining numbers is (n/2)(1 + n) - (x + x+1).

Step 3: Find the number of remaining numbers:
1. We know that the remaining numbers are (n-2).
2. So, the sum of the remaining numbers can also be calculated as the arithmetic mean multiplied by the number of remaining numbers: (105/4)(n-2).

Step 4: Equate the two expressions for the sum of the remaining numbers:
1. Equate the two expressions obtained in Step 2 and Step 3: (n/2)(1 + n) - (x + x+1) = (105/4)(n-2).
2. Simplify the equation.

Step 5: Solve the equation:
1. Multiply the equation by 4 to eliminate the fraction: 2(n^2 + n) - 8(x + x+1) = 105(n-2).
2. Simplify and rearrange the equation to obtain a quadratic equation in terms of n: 2n^2 + 2n - 8x - 8 - 105n + 210 = 0.
3. Combine the terms to get: 2n^2 - 103n + 202 - 8x = 0.
4. This is a quadratic equation in n, and we can solve it using the quadratic formula.

Step 6: Find the values of n, x, and x+1:
1. Solve the quadratic equation using the quadratic formula: n = (-b ± √(b^2 - 4ac))/(2a), where a = 2, b = -103, and c = 202 - 8x.
2. Substitute the obtained values of n in the equation (n/2)(1 + n) - (x + x+1) = (105/4)(n-2) to find the values of x and x+1.

Step 7: Check the validity of the solution:
1. Check if the obtained values of n, x, and x+1 satisfy all the given conditions.
2. Verify that the removed
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Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic mean of the remaining numbers is 105/4. Find n and those removed numbers?
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Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic mean of the remaining numbers is 105/4. Find n and those removed numbers? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic mean of the remaining numbers is 105/4. Find n and those removed numbers? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two consecutive numbers from 1, 2, 3,., n are removed. The arithmetic mean of the remaining numbers is 105/4. Find n and those removed numbers?.
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