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 A ship of mass 3×107 kg initially at rest, is pulled by a force of 5×104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is 
  • a)
    5 m/s 
  • b)
    60 m/s 
  • c)
    1.5 m/s 
  • d)
    0.1 m/s
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A ship of mass 3×107kg initially at rest, is pulled by a force o...
Acceleration provided by the acting force, a = 50000N / 30000000kg = 5/3000 m/s2 
As the acceleration is only provided to a distance of 3m
Thus net velocity, v = √2as
=  (2 x 5/3000 x 3)1/2 m/s
=   1/10 m/s
= 0.1 m/s
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Most Upvoted Answer
A ship of mass 3×107kg initially at rest, is pulled by a force o...
00,000 kg is moving at a speed of 10 m/s. It comes to a sudden stop in 5 seconds. Calculate the force required to stop the ship.

Using the equation F = ma, where F is the force, m is the mass, and a is the acceleration, we can rearrange the equation to solve for force:

F = m * a

First, we need to calculate the acceleration of the ship:

Acceleration = Change in velocity / Time taken
Acceleration = (0 m/s - 10 m/s) / 5 s
Acceleration = -2 m/s^2

Now we can plug in the values to calculate the force:

F = 300,000 kg * -2 m/s^2
F = -600,000 N

Therefore, the force required to stop the ship is 600,000 N in the opposite direction of its motion.
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A ship of mass 3×107kg initially at rest, is pulled by a force of 5×104N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship isa)5 m/sb)60 m/sc)1.5 m/sd)0.1 m/sCorrect answer is option 'D'. Can you explain this answer?
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