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When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is [NEET 2016]
- a)5/2 λ
- b)3 λ
- c)4 λ
- d)5 λ
Correct answer is option 'B'. Can you explain this answer?
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When a metallic surface is illuminated with radiation of wavelength &l...
Λ, the surface may exhibit a phenomenon known as the photoelectric effect. The photoelectric effect is the emission of electrons from a material when it absorbs photons with sufficient energy.
The energy of a photon is given by E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the radiation.
If the energy of a photon is greater than the work function (Φ) of the material, which is the minimum energy required to remove an electron from the surface, then electrons will be emitted. The work function depends on the material and is typically in the range of a few electron volts (eV).
The number of electrons emitted and their kinetic energy depend on the intensity of the radiation, the frequency (or wavelength) of the radiation, and the properties of the material. Higher intensity radiation will result in a larger number of emitted electrons, while higher frequency (or shorter wavelength) radiation will result in electrons with higher kinetic energy.
The photoelectric effect played a crucial role in the development of quantum mechanics, as it provided evidence for the particle-like behavior of light and the quantization of energy. It also has practical applications in technologies such as solar cells and photodetectors.
The energy of a photon is given by E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the radiation.
If the energy of a photon is greater than the work function (Φ) of the material, which is the minimum energy required to remove an electron from the surface, then electrons will be emitted. The work function depends on the material and is typically in the range of a few electron volts (eV).
The number of electrons emitted and their kinetic energy depend on the intensity of the radiation, the frequency (or wavelength) of the radiation, and the properties of the material. Higher intensity radiation will result in a larger number of emitted electrons, while higher frequency (or shorter wavelength) radiation will result in electrons with higher kinetic energy.
The photoelectric effect played a crucial role in the development of quantum mechanics, as it provided evidence for the particle-like behavior of light and the quantization of energy. It also has practical applications in technologies such as solar cells and photodetectors.
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When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer?
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When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer?.
When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2 λ, the stopping potential is 4/V. The threshold wavelength for the metallic surface is[NEET 2016]a)5/2 λb)3 λc)4 λd)5 λCorrect answer is option 'B'. Can you explain this answer?.
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