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prove that the diagonals of a rhombus are perpendicular at 90'
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prove that the diagonals of a rhombus are perpendicular at 90'
given abcd is a rhombus ab=bc=cd=da rhombus is also a parallelogram ao=oc,ob=odto prove/aob=90'proof in tri aob and tri bocao=oc .....(s)ab=bc .....(s)ob=ob common.....(s)therefore tri aob is congruent to tri boc/aob=/boc /aob+/boc=180 ....linear pair2/aob=180/aob=180/2/aob=90 ........proved
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prove that the diagonals of a rhombus are perpendicular at 90'
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