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The sum of two numbers is 45. Their difference is 1/9 of their sum. Their L.C.M is?
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The sum of two numbers is 45. Their difference is 1/9 of their sum. Th...
Solution:


Given:

Two numbers whose sum is 45 and difference is 1/9 of their sum.

Let's assume:

Let the two numbers be x and y.

Equations:

From the given conditions, we can form the following equations:

  • x + y = 45             [Equation 1]

  • x - y = (1/9) * (x + y)             [Equation 2]



Solving Equations:

We can solve these equations for x and y as follows:

  • Adding Equation 1 and Equation 2:


    • x + y + x - y = 45 + (1/9) * (x + y)

    • 2x = 45 + (1/9) * (x + y)


  • Substituting Equation 1 in above equation:


    • 2x = 45 + (1/9) * 45

    • 2x = 50

    • x = 25


  • Substituting x = 25 in Equation 1:


    • 25 + y = 45

    • y = 20




L.C.M of 25 and 20:

The L.C.M of 25 and 20 can be calculated as follows:

  • Prime factorization of 25: 5 * 5

  • Prime factorization of 20: 2 * 2 * 5

  • Combining the common factors: 2 * 2 * 5 * 5 = 100



Answer:

The L.C.M of the given two numbers is 100.
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