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The velocity time graph of a moving particle is shown in Figure, The acceleration of the particle is
- a)5 m/s2
- b)10 m/s2
- c)20 m/s2
- d)2.5 m/s2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The velocity time graph of a moving particle is shown in Figure, The a...
Explanation:
Velocity-Time Graph Analysis:
- The slope of the velocity-time graph gives the acceleration of the particle.
- If the velocity-time graph is a straight line, the acceleration is constant.
- The acceleration can be calculated by finding the slope of the line.
Calculating Acceleration:
- The acceleration can be calculated using the formula: acceleration = change in velocity / change in time.
- By looking at the graph, we can see that the change in velocity is 10 m/s and the change in time is 4 seconds.
Acceleration Calculation:
- acceleration = 10 m/s / 4 s
- acceleration = 2.5 m/s2
Therefore, the acceleration of the particle is 2.5 m/s2. Hence, the correct answer is option D: 2.5 m/s2
Velocity-Time Graph Analysis:
- The slope of the velocity-time graph gives the acceleration of the particle.
- If the velocity-time graph is a straight line, the acceleration is constant.
- The acceleration can be calculated by finding the slope of the line.
Calculating Acceleration:
- The acceleration can be calculated using the formula: acceleration = change in velocity / change in time.
- By looking at the graph, we can see that the change in velocity is 10 m/s and the change in time is 4 seconds.
Acceleration Calculation:
- acceleration = 10 m/s / 4 s
- acceleration = 2.5 m/s2
Therefore, the acceleration of the particle is 2.5 m/s2. Hence, the correct answer is option D: 2.5 m/s2
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
The velocity time graph of a moving particle is shown in Figure, The a...
AC represents acceleration. initial velocity is 5m/s and final velocity is 10m/s whereas time taken will be t1=2and t2=0
and formula is a=v-u/t
v-u/t2-t1
so,10-5/2-0
5/2
2.5m/s2
thus, acceleration of the particle is 2.5m/s2
hope it will help
and formula is a=v-u/t
v-u/t2-t1
so,10-5/2-0
5/2
2.5m/s2
thus, acceleration of the particle is 2.5m/s2
hope it will help
Community Answer
The velocity time graph of a moving particle is shown in Figure, The a...
Ya because of acceleration is slope so the slope means the ratio of vertical increase over horizontal increase which means a=(10-5)m/s
OVER
(2-0)m/s
because the initial time is rest and final is 2 and the initial velocity is 5 and the final is 10 so acceleration is 2.5 from above formula
OVER
(2-0)m/s
because the initial time is rest and final is 2 and the initial velocity is 5 and the final is 10 so acceleration is 2.5 from above formula
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The velocity time graph of a moving particle is shown in Figure, The acceleration of the particle isa)5 m/s2b)10 m/s2c)20 m/s2d)2.5 m/s2Correct answer is option 'D'. Can you explain this answer?
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