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In a Young's double slit experiment 15 fringes are observed on a small portion of the screen when light
of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when
another light source of wavelength λ is used Then the value of λ is (in nm)
of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when
another light source of wavelength λ is used Then the value of λ is (in nm)
Correct answer is '750'. Can you explain this answer?
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In a Youngs double slit experiment 15 fringes are observed on a small ...
Let's first use the formula for the number of fringes in a Young's double slit experiment:
n = (Dλ) / d
where n is the number of fringes, D is the distance from the slits to the screen, λ is the wavelength of light, and d is the distance between the slits.
For the first light source with wavelength 500 nm, we have:
n1 = (Dλ1) / d
where n1 = 15 and λ1 = 500 nm.
For the second light source with wavelength λ2, we have:
n2 = (Dλ2) / d
where n2 = 10.
We want to find the ratio of the two wavelengths, so let's divide the two equations:
n1/n2 = (Dλ1/d) / (Dλ2/d)
Simplifying:
n1/n2 = λ1 / λ2
Substituting the given values:
15/10 = 500 nm / λ2
Solving for λ2:
λ2 = (500 nm) * (10/15) = 333.33 nm
Therefore, the ratio of the two wavelengths is:
λ1 / λ2 = 500 nm / 333.33 nm = 1.5
So the first wavelength is 1.5 times longer than the second wavelength.
n = (Dλ) / d
where n is the number of fringes, D is the distance from the slits to the screen, λ is the wavelength of light, and d is the distance between the slits.
For the first light source with wavelength 500 nm, we have:
n1 = (Dλ1) / d
where n1 = 15 and λ1 = 500 nm.
For the second light source with wavelength λ2, we have:
n2 = (Dλ2) / d
where n2 = 10.
We want to find the ratio of the two wavelengths, so let's divide the two equations:
n1/n2 = (Dλ1/d) / (Dλ2/d)
Simplifying:
n1/n2 = λ1 / λ2
Substituting the given values:
15/10 = 500 nm / λ2
Solving for λ2:
λ2 = (500 nm) * (10/15) = 333.33 nm
Therefore, the ratio of the two wavelengths is:
λ1 / λ2 = 500 nm / 333.33 nm = 1.5
So the first wavelength is 1.5 times longer than the second wavelength.
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In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer?
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In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer?.
In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer?.
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In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer?, a detailed solution for In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? has been provided alongside types of In a Youngs double slit experiment 15 fringes are observed on a small portion of the screen when lightof wavelength 500 nm is used. Ten fringes are observed on the same section of the screen whenanother light source of wavelength λ is used Then the value of λis (in nm)Correct answer is '750'. Can you explain this answer? theory, EduRev gives you an
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