JEE Exam > JEE Questions > . Two dice are tossed once. The probability o...
Start Learning for Free
. Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 is
- a)1/36
- b)3/36
- c)11/36
- d)20/36
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
. Two dice are tossed once. The probability of getting an even number ...
A = getting even no on 1st dice
B = getting sum 8
B = getting sum 8
Most Upvoted Answer
. Two dice are tossed once. The probability of getting an even number ...
Solution:
Possible outcomes when two dice are tossed once = 6 × 6 = 36
Let E1 be the event of getting an even number on the first die
Let E2 be the event of getting a total of 8
P(E1) = probability of getting an even number on the first die
= 3/6 (as three even numbers are possible on a die)
= 1/2
P(E2) = probability of getting a total of 8
= number of possible outcomes to get a total of 8 / total possible outcomes
= 5/36
(we get a total of 8 when we get (2,6), (3,5), (4,4), (5,3), or (6,2))
P(E1 ∪ E2) = probability of getting an even number on the first die or a total of 8
= P(E1) + P(E2) - P(E1 ∩ E2)
(where P(E1 ∩ E2) is the probability of getting an even number on the first die and a total of 8, which is not possible)
= 1/2 + 5/36
= 20/36
Therefore, the probability of getting an even number on the first die or a total of 8 is 20/36 or option D.
Possible outcomes when two dice are tossed once = 6 × 6 = 36
Let E1 be the event of getting an even number on the first die
Let E2 be the event of getting a total of 8
P(E1) = probability of getting an even number on the first die
= 3/6 (as three even numbers are possible on a die)
= 1/2
P(E2) = probability of getting a total of 8
= number of possible outcomes to get a total of 8 / total possible outcomes
= 5/36
(we get a total of 8 when we get (2,6), (3,5), (4,4), (5,3), or (6,2))
P(E1 ∪ E2) = probability of getting an even number on the first die or a total of 8
= P(E1) + P(E2) - P(E1 ∩ E2)
(where P(E1 ∩ E2) is the probability of getting an even number on the first die and a total of 8, which is not possible)
= 1/2 + 5/36
= 20/36
Therefore, the probability of getting an even number on the first die or a total of 8 is 20/36 or option D.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
. Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer?
Question Description
. Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer?.
. Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer?.
Solutions for . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
. Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer?, a detailed solution for . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice . Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 isa)1/36b)3/36c)11/36d)20/36Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup