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The roots of the quadratic equation x2 - 2√3x - 22 = 0 are :
- a)imaginry
- b)real, rational and equal
- c)real, irrational and unequal
- d)real, rational and unequal
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The roots of the quadratic equation x2 - 2√3x - 22 = 0 are :a)im...
The equation x^2 - 2 = 0 is a quadratic equation. To find the roots of this equation, we can use the quadratic formula.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the roots are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 0, and c = -2. Plugging these values into the quadratic formula, we have:
x = (0 ± √(0^2 - 4(1)(-2))) / (2(1))
Simplifying further:
x = (± √(0 + 8)) / 2
x = (± √8) / 2
x = ± √2
Therefore, the roots of the quadratic equation x^2 - 2 = 0 are x = √2 and x = -√2.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the roots are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 0, and c = -2. Plugging these values into the quadratic formula, we have:
x = (0 ± √(0^2 - 4(1)(-2))) / (2(1))
Simplifying further:
x = (± √(0 + 8)) / 2
x = (± √8) / 2
x = ± √2
Therefore, the roots of the quadratic equation x^2 - 2 = 0 are x = √2 and x = -√2.
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The roots of the quadratic equation x2 - 2√3x - 22 = 0 are :a)im...
Missing of sign of constant term
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The roots of the quadratic equation x2 - 2√3x - 22 = 0 are :a)imaginryb)real, rational and equalc)real, irrational and unequald)real, rational and unequalCorrect answer is option 'C'. Can you explain this answer?
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