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The probability of getting 53 Sundays in a leap year is
  • a)
    1/7
  • b)
    2/7
  • c)
    3/7
  • d)
    4/7
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The probability of getting 53 Sundays in a leap year isa)1/7b)2/7c)3/7...
Explanation:
To determine the probability of getting 53 Sundays in a leap year, we need to consider the number of days in a leap year and the number of days in a week.

Number of days in a leap year:
A leap year has 366 days instead of the usual 365 days. This is because an extra day, February 29th, is added to the calendar.

Number of days in a week:
A week has 7 days.

Calculating the probability:
To calculate the probability of getting 53 Sundays in a leap year, we need to determine the total number of possibilities and the favorable outcomes.

Total number of possibilities:
In a leap year, there are 366 days. Each day can be either a Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday. Therefore, the total number of possibilities is 7^366 (7 raised to the power of 366).

Favorable outcomes:
We want to find the number of ways to choose 53 Sundays out of the 366 days. This can be calculated using combinations. The number of ways to choose 53 Sundays out of 366 days is denoted as C(366, 53) and can be calculated as:

C(366, 53) = 366! / (53!(366-53)!)

Using the formula for combinations, we can calculate the number of favorable outcomes.

Calculating the probability:
The probability is given by the number of favorable outcomes divided by the total number of possibilities:

Probability = Number of favorable outcomes / Total number of possibilities

Substituting the values we calculated, we have:

Probability = C(366, 53) / (7^366)

Simplifying this expression may not be feasible due to the large numbers involved. However, we can determine the approximate probability using a calculator or software.

The correct answer provided in the options is 'B' (2/7).
Free Test
Community Answer
The probability of getting 53 Sundays in a leap year isa)1/7b)2/7c)3/7...
The answer is b
2/7
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