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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?
  • a)
    A metre scale
  • b)
    A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm
  • c)
    A screw gauge having 100 divisions in the circular scale and pitch as 1 mm
  • d)
    A screw guage having 50 divisions in the circular scale and pitch as 1 mm
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A student measured the length of a rod and wrote it as 3.50 cm. Which ...
As the measured value is 3.50 cm, the least count must be 0.01 cm = 0.1 mm
For vernier callipper with MSD = 1 mm and 9 MSD = 10 VSD,
Least count = 1 MSD – 1 VSD = 0.1 mm
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Most Upvoted Answer
A student measured the length of a rod and wrote it as 3.50 cm. Which ...
Instrument Used: A Vernier Calliper

Explanation:
To determine the instrument used to measure the length of the rod, let's analyze the given options:

a) A metre scale: A metre scale typically measures lengths in centimeters or millimeters. However, since the recorded measurement is given as 3.50 cm, it is unlikely that a metre scale was used. Therefore, option a) can be ruled out.

b) A vernier calliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and the main scale has 10 divisions in 1 cm: This option seems plausible because a vernier calliper is capable of measuring lengths with high precision. The given details about the 10:9 ratio between the vernier and main scales are consistent with the design of a vernier calliper. Hence, option b) is a likely candidate.

c) A screw gauge having 100 divisions in the circular scale and pitch as 1 mm: A screw gauge is primarily used to measure small lengths, typically in the sub-millimeter range. The recorded measurement of 3.50 cm is much larger than what a screw gauge is typically used for. Therefore, option c) can be ruled out.

d) A screw gauge having 50 divisions in the circular scale and pitch as 1 mm: Similar to option c), this option involves a screw gauge that is intended for measuring small lengths. The recorded measurement of 3.50 cm is significantly larger than what a screw gauge is typically used for, so option d) can also be eliminated.

Conclusion:
By process of elimination, the most likely instrument used to measure the length of the rod is a vernier calliper as described in option b). This instrument allows for precise measurements and the given details about the scale divisions align with the design of a vernier calliper.
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A student measured the length of a rod and wrote it as 3.50 cm. Which ...
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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?a)A metre scaleb)A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cmc)A screw gauge having 100 divisions in the circular scale and pitch as 1 mmd)A screw guage having 50 divisions in the circular scale and pitch as 1 mmCorrect answer is option 'B'. Can you explain this answer?
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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?a)A metre scaleb)A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cmc)A screw gauge having 100 divisions in the circular scale and pitch as 1 mmd)A screw guage having 50 divisions in the circular scale and pitch as 1 mmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?a)A metre scaleb)A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cmc)A screw gauge having 100 divisions in the circular scale and pitch as 1 mmd)A screw guage having 50 divisions in the circular scale and pitch as 1 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?a)A metre scaleb)A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cmc)A screw gauge having 100 divisions in the circular scale and pitch as 1 mmd)A screw guage having 50 divisions in the circular scale and pitch as 1 mmCorrect answer is option 'B'. Can you explain this answer?.
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