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The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)
- a)6.64 cm
- b)6.42 cm
- c)6.44 cm
- d)6.13 cm
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The thin metallic strip of vernier callipers moves downward from top t...
Reading = 6.4 + 4 × 0.01 cm = 6.44 cm
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The thin metallic strip of vernier callipers moves downward from top t...
Given:
Main scale reading = 6.4 cm
Vernier constant = 0.1 mm
4th vernier scale division coincides with main scale division
To find:
The actual depth of the beaker
Explanation:
Step 1: Understanding the main scale and vernier scale:
The main scale of the vernier caliper is represented by the main scale reading, which in this case is 6.4 cm. The vernier scale is used to measure more precise readings and consists of multiple divisions.
Step 2: Identifying the vernier constant:
The vernier constant is the difference between one division on the main scale and one division on the vernier scale. In this case, the vernier constant is given as 0.1 mm.
Step 3: Determining the position of the vernier scale:
The question states that the 4th division of the vernier scale coincides with a division on the main scale. This means that the 4th division on the vernier scale aligns with a division on the main scale.
Step 4: Calculating the actual depth of the beaker:
To calculate the actual depth of the beaker, we need to add the main scale reading to the product of the vernier constant and the number of divisions on the vernier scale that coincide with divisions on the main scale.
The number of divisions on the vernier scale that coincide with divisions on the main scale can be determined by counting the number of divisions from the zero point of the vernier scale to the point where the vernier scale aligns with the main scale.
In this case, the main scale reading is 6.4 cm, and the vernier constant is 0.1 mm. Since the 4th division on the vernier scale coincides with a division on the main scale, the number of divisions on the vernier scale that coincide with divisions on the main scale is 4.
Therefore, the actual depth of the beaker is:
6.4 cm + (0.1 mm * 4) = 6.4 cm + 0.4 mm = 6.44 cm
Hence, the correct answer is option C) 6.44 cm.
Main scale reading = 6.4 cm
Vernier constant = 0.1 mm
4th vernier scale division coincides with main scale division
To find:
The actual depth of the beaker
Explanation:
Step 1: Understanding the main scale and vernier scale:
The main scale of the vernier caliper is represented by the main scale reading, which in this case is 6.4 cm. The vernier scale is used to measure more precise readings and consists of multiple divisions.
Step 2: Identifying the vernier constant:
The vernier constant is the difference between one division on the main scale and one division on the vernier scale. In this case, the vernier constant is given as 0.1 mm.
Step 3: Determining the position of the vernier scale:
The question states that the 4th division of the vernier scale coincides with a division on the main scale. This means that the 4th division on the vernier scale aligns with a division on the main scale.
Step 4: Calculating the actual depth of the beaker:
To calculate the actual depth of the beaker, we need to add the main scale reading to the product of the vernier constant and the number of divisions on the vernier scale that coincide with divisions on the main scale.
The number of divisions on the vernier scale that coincide with divisions on the main scale can be determined by counting the number of divisions from the zero point of the vernier scale to the point where the vernier scale aligns with the main scale.
In this case, the main scale reading is 6.4 cm, and the vernier constant is 0.1 mm. Since the 4th division on the vernier scale coincides with a division on the main scale, the number of divisions on the vernier scale that coincide with divisions on the main scale is 4.
Therefore, the actual depth of the beaker is:
6.4 cm + (0.1 mm * 4) = 6.4 cm + 0.4 mm = 6.44 cm
Hence, the correct answer is option C) 6.44 cm.
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The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer?
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The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer?.
The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The thin metallic strip of vernier callipers moves downward from top to bottom in such a way that it just touches the surface of beaker. Main scale reading of calliper is 6.4 cm whereas its vernier constant is 0.1 mm. The 4th of vernier scale division is coinciding with main scale division. The actual depth of beaker is (when zero of vernier coincides with zero of main scale)a)6.64 cmb)6.42 cmc)6.44 cmd)6.13 cmCorrect answer is option 'C'. Can you explain this answer?.
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