JEE Exam > JEE Questions > A bullet losses 1/n of its velocity in passin...
Start Learning for Free
A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)?
Most Upvoted Answer
A bullet losses 1/n of its velocity in passing through a plank. What i...
Solution:
Introduction:
When a bullet passes through a plank, it loses 1/n of its velocity. We need to find the minimum number of planks required to stop the bullet.
Concept:
The velocity of the bullet decreases by a factor of 1/n after passing through each plank. We can use the formula for velocity after a certain distance covered with constant retardation, V² - U² = 2as, where V is the final velocity, U is the initial velocity, a is the retardation, and s is the distance covered.
Calculation:
Let the initial velocity of the bullet be U. After passing through the first plank, the velocity becomes U/n. To stop the bullet, the final velocity should be zero. Therefore, the distance covered by the bullet after passing through the first plank is given by:
(U/n)² - U² = -2as
On simplifying, we get:
s = (n² - 1)U²/2an²
The bullet has to pass through n planks. Therefore, the total distance covered by the bullet is:
S = n((n² - 1)U²/2an²)
We need to find the minimum value of n such that S is greater than or equal to the thickness of the planks.
Conclusion:
In conclusion, the minimum number of planks required to stop the bullet is given by:
n = √((U²t)/(2a(U²/n² - U²)))
where t is the thickness of the plank.
Introduction:
When a bullet passes through a plank, it loses 1/n of its velocity. We need to find the minimum number of planks required to stop the bullet.
Concept:
The velocity of the bullet decreases by a factor of 1/n after passing through each plank. We can use the formula for velocity after a certain distance covered with constant retardation, V² - U² = 2as, where V is the final velocity, U is the initial velocity, a is the retardation, and s is the distance covered.
Calculation:
Let the initial velocity of the bullet be U. After passing through the first plank, the velocity becomes U/n. To stop the bullet, the final velocity should be zero. Therefore, the distance covered by the bullet after passing through the first plank is given by:
(U/n)² - U² = -2as
On simplifying, we get:
s = (n² - 1)U²/2an²
The bullet has to pass through n planks. Therefore, the total distance covered by the bullet is:
S = n((n² - 1)U²/2an²)
We need to find the minimum value of n such that S is greater than or equal to the thickness of the planks.
Conclusion:
In conclusion, the minimum number of planks required to stop the bullet is given by:
n = √((U²t)/(2a(U²/n² - U²)))
where t is the thickness of the plank.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)?
Question Description
A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)?.
A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)?.
Solutions for A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? defined & explained in the simplest way possible. Besides giving the explanation of
A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)?, a detailed solution for A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? has been provided alongside types of A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? theory, EduRev gives you an
ample number of questions to practice A bullet losses 1/n of its velocity in passing through a plank. What is the least no. Of planks required to stop the bullet? (assume constant acceleration)? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup