You are given two metal sheets of mica of thickness 2×10^-5m . calcula...
Calculation of Area of Metal Required to Construct a Capacitor
Given Data
- Thickness of each metal sheet (mica) = 2×10^-5m
- Capacity of capacitor (C) = 0.02 micro faraday
Formula Used
The capacitance of a parallel plate capacitor is given by:
C = εA/d
where:
- C = capacitance of the capacitor (in farads)
- ε = permittivity of the medium between the plates (in farads/meter)
- A = area of each plate (in square meters)
- d = distance between the plates (in meters)
Calculation
Since the thickness of each metal sheet (mica) is given, the distance between the plates (d) is:
d = 2 × thickness
Therefore, the distance between the plates (d) is:
d = 2 × 2×10^-5m = 4×10^-5m
Permittivity of the medium between the plates (ε) is a constant and its value is:
ε = 8.85 × 10^-12 farads/meter
Now, using the formula for capacitance, we can calculate the area of each plate (A) as follows:
A = Cd/ε
Substituting the given values, we get:
A = (0.02×10^-6 F) × (4×10^-5m) / (8.85×10^-12 F/m)
Solving the above equation, we get:
A = 0.0904 m^2
Final Answer
The area of metal required to construct a capacitor of capacity 0.02 micro faraday is 0.0904 square meters.