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Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)
- a)138.5
- b)155.5
- c)172.5
- d)199.5
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of...
C = 84/12 = 7 mole
H2 = 12 g = 6 mole
O2 = 56/22.4 = 5/2 mole
12C + 11H2 + 11/2 O2 → C12H22O11
L.R. = O2
11/2 mole O2 produce 1 mole sucrose 5/2 mole O2 will for 5/11 mole sucrose mass of sucrose = 5/11 × (mol. mass)
= 5/11 × 342
= 155.45 g
Most Upvoted Answer
Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of...
To calculate the mass of sucrose produced, we need to first balance the chemical equation for the reaction between carbon, hydrogen, and oxygen to form sucrose:
C12H22O11 + 12 O2 → 12 CO2 + 11 H2O
From the balanced equation, we can see that 12 moles of sucrose are produced for every 12 moles of oxygen consumed. Therefore, we need to calculate the number of moles of oxygen consumed in the reaction:
PV = nRT
n = PV/RT
n = (1 atm)(56 L)/(0.0821 L·atm·K−1·mol−1)(298 K)
n = 2.26 mol O2
Since we need 12 moles of oxygen to produce 12 moles of sucrose, we know that the maximum amount of sucrose that can be produced is 1/12th of the amount of oxygen consumed:
n = 2.26 mol O2 × (1 mol sucrose/12 mol O2) = 0.188 mol sucrose
Finally, we can calculate the mass of sucrose produced using the molar mass of sucrose:
m = nM
m = (0.188 mol)(342.3 g/mol)
m = 64.4 g sucrose
Therefore, the mass of sucrose produced by mixing 84 gm of carbon, 12 gm of hydrogen, and 56 L of oxygen at 1 atm is approximately 64.4 grams.
C12H22O11 + 12 O2 → 12 CO2 + 11 H2O
From the balanced equation, we can see that 12 moles of sucrose are produced for every 12 moles of oxygen consumed. Therefore, we need to calculate the number of moles of oxygen consumed in the reaction:
PV = nRT
n = PV/RT
n = (1 atm)(56 L)/(0.0821 L·atm·K−1·mol−1)(298 K)
n = 2.26 mol O2
Since we need 12 moles of oxygen to produce 12 moles of sucrose, we know that the maximum amount of sucrose that can be produced is 1/12th of the amount of oxygen consumed:
n = 2.26 mol O2 × (1 mol sucrose/12 mol O2) = 0.188 mol sucrose
Finally, we can calculate the mass of sucrose produced using the molar mass of sucrose:
m = nM
m = (0.188 mol)(342.3 g/mol)
m = 64.4 g sucrose
Therefore, the mass of sucrose produced by mixing 84 gm of carbon, 12 gm of hydrogen, and 56 L of oxygen at 1 atm is approximately 64.4 grams.
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Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer?
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Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer?.
Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Mass of sucrose C12H22O11 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O2 at 1 atm & 273 K according to given reaction, is C(s) + H2(g) + O2(g) → C12H22O11 (s)a)138.5b)155.5c)172.5d)199.5Correct answer is option 'B'. Can you explain this answer?.
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