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A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place?
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A number when reversed becomes 45% greater than original. By how much ...
Problem Statement: A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten's place digit place?
Solution:
Let's assume the number to be AB (where A is the tens place digit and B is the units place digit).
When the number is reversed, it becomes BA, which is 45% greater than the original number AB.
Mathematically, we can represent this as:
BA = AB + 0.45AB
Simplifying this equation, we get:
BA = 1.45AB
Now, we can substitute BA with 10A + B and AB with 10B + A (since A is in the tens place and B is in the units place).
So, we get:
10A + B = 1.45(10B + A)
Simplifying this equation, we get:
5A = 4B
Therefore, the percentage by which the units place digit (B) is greater than the tens place digit (A) can be calculated as:
Percentage increase = (B - A)/A x 100
Substituting 5A/4 for B, we get:
Percentage increase = (5A/4 - A)/A x 100
Simplifying this equation, we get:
Percentage increase = 25%
Therefore, the units place digit is 25% greater than the tens place digit in the original number.
Conclusion:
The units place digit is 25% greater than the tens place digit in the original number.
Solution:
Let's assume the number to be AB (where A is the tens place digit and B is the units place digit).
When the number is reversed, it becomes BA, which is 45% greater than the original number AB.
Mathematically, we can represent this as:
BA = AB + 0.45AB
Simplifying this equation, we get:
BA = 1.45AB
Now, we can substitute BA with 10A + B and AB with 10B + A (since A is in the tens place and B is in the units place).
So, we get:
10A + B = 1.45(10B + A)
Simplifying this equation, we get:
5A = 4B
Therefore, the percentage by which the units place digit (B) is greater than the tens place digit (A) can be calculated as:
Percentage increase = (B - A)/A x 100
Substituting 5A/4 for B, we get:
Percentage increase = (5A/4 - A)/A x 100
Simplifying this equation, we get:
Percentage increase = 25%
Therefore, the units place digit is 25% greater than the tens place digit in the original number.
Conclusion:
The units place digit is 25% greater than the tens place digit in the original number.
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A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place?
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A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place?.
A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A number when reversed becomes 45% greater than original. By how much percentage is the units place greater than ten s place digit place?.
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