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A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the plane
- a)remains constant
- b)first decreases then increases
- c)first remains constant then decreases
- d)first increases then decreases
Correct answer is option 'C'. Can you explain this answer?
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A body is placed on a rough inclined plane of inclination θ. As ...
Θ with the horizontal. The body has a mass of m and the coefficient of kinetic friction between the body and the plane is μ. The body is released from rest at the top of the plane and slides down the plane. The acceleration of the body down the plane is given by:
a = g sinθ - μg cosθ
where g is the acceleration due to gravity.
The first term on the right-hand side of the equation represents the component of the gravitational force acting down the plane, while the second term represents the frictional force acting up the plane. As the body slides down the plane, the frictional force opposes the motion and reduces the acceleration. When the body reaches the bottom of the plane, its speed will be:
v = √(2gh sinθ/(1 + μ cosθ))
where h is the vertical distance travelled by the body down the plane.
The work done by gravity on the body as it slides down the plane is given by:
W = mgh sinθ
where W is the work done, and h is the vertical distance travelled by the body down the plane. This work is converted into kinetic energy of the body at the bottom of the plane, given by:
K = 1/2 mv^2
where K is the kinetic energy of the body.
The efficiency of the system is given by:
η = K/W
where η is the efficiency of the system. This represents the fraction of the work done by gravity that is converted into kinetic energy of the body at the bottom of the plane. The efficiency is always less than 1, as some of the work done by gravity is lost due to friction.
a = g sinθ - μg cosθ
where g is the acceleration due to gravity.
The first term on the right-hand side of the equation represents the component of the gravitational force acting down the plane, while the second term represents the frictional force acting up the plane. As the body slides down the plane, the frictional force opposes the motion and reduces the acceleration. When the body reaches the bottom of the plane, its speed will be:
v = √(2gh sinθ/(1 + μ cosθ))
where h is the vertical distance travelled by the body down the plane.
The work done by gravity on the body as it slides down the plane is given by:
W = mgh sinθ
where W is the work done, and h is the vertical distance travelled by the body down the plane. This work is converted into kinetic energy of the body at the bottom of the plane, given by:
K = 1/2 mv^2
where K is the kinetic energy of the body.
The efficiency of the system is given by:
η = K/W
where η is the efficiency of the system. This represents the fraction of the work done by gravity that is converted into kinetic energy of the body at the bottom of the plane. The efficiency is always less than 1, as some of the work done by gravity is lost due to friction.
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A body is placed on a rough inclined plane of inclination θ. As ...
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A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer?
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A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer?.
A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer?.
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A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A body is placed on a rough inclined plane of inclination θ. As the angle θ is increased from 0º to 90º the contact force between the block and the planea)remains constantb)first decreases then increasesc)first remains constant then decreasesd)first increases then decreasesCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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