Given information:
- Initial speed (u) = 0 km/h (since the train is starting from rest)
- Final speed (v) = 40 km/h
- Time taken (t) = 10 minutes = 10/60 = 1/6 hours

Formula:
The formula to calculate acceleration (a) is:
a = (v - u) / t

Calculation:
Substituting the given values into the formula, we get:
a = (40 - 0) / (1/6)
a = 240 km/h²

However, the answer is expected in m/s², so we need to convert the units.

Unit Conversion:
1 km = 1000 m
1 hour = 3600 seconds

Converting the initial speed:
0 km/h = 0 m/s

Converting the final speed:
40 km/h = (40 * 1000) / 3600 m/s
= 40000 / 3600 m/s
= 100/9 m/s

Converting the time:
1/6 hours = (1/6) * 3600 seconds
= 600 seconds

Now, substituting the converted values into the formula:
a = (100/9 - 0) / 600
a = 100/5400
a = 1/54 m/s²

Therefore, the acceleration of the train is 1/54 m/s².

Explanation:
The given problem is about a train that starts from rest and attains a speed of 40 km/h in 10 minutes. To find the acceleration, we need to use the formula a = (v - u) / t, where v is the final speed, u is the initial speed, and t is the time taken.

First, we substitute the given values into the formula. The initial speed is 0 km/h since the train is starting from rest. The final speed is 40 km/h, and the time taken is 10 minutes.

After substituting the values, we calculate the acceleration in km/h². However, the answer is expected in m/s², so we need to convert the units.

Converting the initial speed and final speed from km/h to m/s, we use the conversion factors 1 km = 1000 m and 1 hour = 3600 seconds.

Next, we convert the time from hours to seconds. Now, we have all the values in the correct units.

Substituting the converted values into the formula, we calculate the acceleration in m/s².

Therefore, the acceleration of the train is 1/54 m/s².

u_0v_200/18m/st_600seca_v-u/t200/18:1/100=2/18=.111.......ms2