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A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _
- a)WL2rI
- b)WL2rM
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A cube of iron whose sides are of length L, is put into mercury. The w...
The height of the block above the mercury level is h = 4.71 cm
Explanation:
Correct statement:
A cubical iron block of side 10 cm is floating on mercury in a vessel. What is the height of the block above the mercury level?
Given that the density of iron is 7.2 gm/c.c and density of the mercury =13.6 gm/c.c
Give data:
Density of iron is 7.2 gm/cm^3
Density of the mercury =13.6 gm/cm^3
Length of side of iron block = 10 cm
Let height of the lock = x
Volume of lock inside mercury = 10 x 10 x(10-x)
Weight of this volume of mercury = vm x 13.6 x 981 = upthrust on block
Total volume of block = 10 x 10 x 10 = 1000 cm^3
Weight "W" = Vρig = V x 7.2 x 981
Weight of mercury displaced = Weight of iron block
100 x (10-x) x 13.6 x 981 = 1000 x 7.2 x 981
100 x (10-x) x 13.6 = 1000 x 7.2
(10-x) x 1360 = 7200
10-x = 7200 / 1360
10-x = 5.29
10 - 5.29 = x
h = 4.71 cm
The height of the block above the mercury level is h = 4.71 cm
Also learn about
What is retardation ?
Explanation:
Correct statement:
A cubical iron block of side 10 cm is floating on mercury in a vessel. What is the height of the block above the mercury level?
Given that the density of iron is 7.2 gm/c.c and density of the mercury =13.6 gm/c.c
Give data:
Density of iron is 7.2 gm/cm^3
Density of the mercury =13.6 gm/cm^3
Length of side of iron block = 10 cm
Let height of the lock = x
Volume of lock inside mercury = 10 x 10 x(10-x)
Weight of this volume of mercury = vm x 13.6 x 981 = upthrust on block
Total volume of block = 10 x 10 x 10 = 1000 cm^3
Weight "W" = Vρig = V x 7.2 x 981
Weight of mercury displaced = Weight of iron block
100 x (10-x) x 13.6 x 981 = 1000 x 7.2 x 981
100 x (10-x) x 13.6 = 1000 x 7.2
(10-x) x 1360 = 7200
10-x = 7200 / 1360
10-x = 5.29
10 - 5.29 = x
h = 4.71 cm
The height of the block above the mercury level is h = 4.71 cm
Also learn about
What is retardation ?
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A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer? for Class 11 2026 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer?.
A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer? for Class 11 2026 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cube of iron whose sides are of length L, is put into mercury. The weight of iron cube is W. The density of iron is rI, that of mercury is rM. The depth to which the cube sinks is given by the expression _a)WL2rIb)WL2rMc)d)Correct answer is option 'D'. Can you explain this answer?.
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