11 :b : 44 are in continued proportion. Find b.a)4b)22c)44d)11Correct ...
We know that if a, b and c are in continued proportion then b2 = ac
b2 = 11.44
b2 = 484
b = 22
11 :b : 44 are in continued proportion. Find b.a)4b)22c)44d)11Correct ...
Given:
- Ratio of gold and silver in first alloy = 1:2
- Ratio of gold and silver in second alloy = 2:3
- Ratio of gold and silver in the new alloy = 3:5
To find:
- Parts of the two alloys needed to obtain the new alloy
Solution:
Let's assume that x parts of the first alloy and y parts of the second alloy are taken to form the new alloy.
Gold ratio in first alloy = 1/(1+2) = 1/3
Silver ratio in first alloy = 2/(1+2) = 2/3
Gold ratio in second alloy = 2/(2+3) = 2/5
Silver ratio in second alloy = 3/(2+3) = 3/5
Gold ratio in new alloy = 3/(3+5) = 3/8
Silver ratio in new alloy = 5/(3+5) = 5/8
We need to find x and y such that the ratio of gold and silver in the new alloy is 3:5.
- Gold in new alloy = (x*1/3) + (y*2/5) = (3/8)*(x+y)
- Silver in new alloy = (x*2/3) + (y*3/5) = (5/8)*(x+y)
We can solve these two equations to get the values of x and y.
Multiplying the first equation by 15 and the second equation by 24, we get:
- 5x + 6y = 9(x+y)
- 8x + 18y = 15(x+y)
Simplifying these equations, we get:
- 4x - 3y = 0
- 3x - 6y = 0
Solving these equations, we get:
x = 3y/2
Substituting this value of x in the first equation, we get:
5y = 24(x+y)/8
Simplifying this equation, we get:
y = 5
Substituting this value of y in the equation x = 3y/2, we get:
x = 7.5
Therefore, the parts of the two alloys needed to obtain the new alloy are 7.5 and 5.
Answer:
Option (B) 3 and 5.