During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2?

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During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2?

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Read the passage given below and answer the following questions:EVIDENCE FOR THE FIBROUS NATURE OF DNAThe basic chemical formula of DNA is now well established. As shown in Figure 1 it consists of a very long chain, the backbone of which is made up of alternate sugar and phosphate groups, joined together in regular 3’ 5’ phosphate di-ester linkages. To each sugar is attached a nitrogenous base, only four different kinds of which are commonly found in DNA. Two of these---adenine and guanine--- are purines, and the other two thymine and cytosine-are pyrimidines. A fifth base, 5-methyl cytosine, occurs in smaller amounts in certain organisms, and a sixth, 5-hydroxy-methyl-cytosine, is found instead of cytosine in the T even phages. It should be noted that the chain is unbranched, a consequence of the regular internucleotide linkage. On the other hand the sequence of the different nucleotides is, as far as can be ascertained,completely irregular. Thus, DNA has some features which are regular, and some which are irregular. A similar conception of the DNA molecule as a long thin fiber is obtained from physicochemical analysis involving sedimentation, diffusion, light scattering, and viscosity measurements. These techniques indicate that DNA is a very asymmetrical structure approximately 20 A wide and many thousands of angstroms long. Estimates of its molecular weight currently center between 5 X106 and X107 (approximately 3 X104 nucleotides). Surprisingly each of these measurements tend to suggest that the DNA is relatively rigid, a puzzling finding in view of the large number of single bonds (5 per nucleotid e) in the phosphate-sugar back bone. Recently these indirect inferences have been confirmed by electron microscopy.Q. Out of the four different kinds of nitrogenous bases which are commonly found in DNA, ___________ has been replaced in some organisms.

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Read the passage given below and answer the following questions:EVIDENCE FOR THE FIBROUS NATURE OF DNAThe basic chemical formula of DNA is now well established. As shown in Figure 1 it consists of a very long chain, the backbone of which is made up of alternate sugar and phosphate groups, joined together in regular 3’ 5’ phosphate di-ester linkages. To each sugar is attached a nitrogenous base, only four different kinds of which are commonly found in DNA. Two of these---adenine and guanine--- are purines, and the other two thymine and cytosine-are pyrimidines. A fifth base, 5-methyl cytosine, occurs in smaller amounts in certain organisms, and a sixth, 5-hydroxy-methyl-cytosine, is found instead of cytosine in the T even phages. It should be noted that the chain is unbranched, a consequence of the regular internucleotide linkage. On the other hand the sequence of the different nucleotides is, as far as can be ascertained,completely irregular. Thus, DNA has some features which are regular, and some which are irregular. A similar conception of the DNA molecule as a long thin fiber is obtained from physicochemical analysis involving sedimentation, diffusion, light scattering, and viscosity measurements. These techniques indicate that DNA is a very asymmetrical structure approximately 20 A wide and many thousands of angstroms long. Estimates of its molecular weight currently center between 5 X106 and X107 (approximately 3 X104 nucleotides). Surprisingly each of these measurements tend to suggest that the DNA is relatively rigid, a puzzling finding in view of the large number of single bonds (5 per nucleotid e) in the phosphate-sugar back bone. Recently these indirect inferences have been confirmed by electron microscopy.Q. DNA molecule has _ internucleotide linkage and sequence of the different nucleotides

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Read the passage given below and answer the following questions:EVIDENCE FOR THE FIBROUS NATURE OF DNAThe basic chemical formula of DNA is now well established. As shown in Figure 1 it consists of a very long chain, the backbone of which is made up of alternate sugar and phosphate groups, joined together in regular 3’ 5’ phosphate di-ester linkages. To each sugar is attached a nitrogenous base, only four different kinds of which are commonly found in DNA. Two of these---adenine and guanine--- are purines, and the other two thymine and cytosine-are pyrimidines. A fifth base, 5-methyl cytosine, occurs in smaller amounts in certain organisms, and a sixth, 5-hydroxy-methyl-cytosine, is found instead of cytosine in the T even phages. It should be noted that the chain is unbranched, a consequence of the regular internucleotide linkage. On the other hand the sequence of the different nucleotides is, as far as can be ascertained,completely irregular. Thus, DNA has some features which are regular, and some which are irregular. A similar conception of the DNA molecule as a long thin fiber is obtained from physicochemical analysis involving sedimentation, diffusion, light scattering, and viscosity measurements. These techniques indicate that DNA is a very asymmetrical structure approximately 20 A wide and many thousands of angstroms long. Estimates of its molecular weight currently center between 5 X106and X107(approximately 3 X104nucleotides). Surprisingly each of these measurements tend to suggest that the DNA is relatively rigid, a puzzling finding in view of the large number of single bonds (5 per nucleotid e) in the phosphate-sugar back bone. Recently these indirect inferences have been confirmed by electron microscopy.Q. Purines present in DNA are

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Read the passage given below and answer the following questions:EVIDENCE FOR THE FIBROUS NATURE OF DNAThe basic chemical formula of DNA is now well established. As shown in Figure 1 it consists of a very long chain, the backbone of which is made up of alternate sugar and phosphate groups, joined together in regular 3’ 5’ phosphate di-ester linkages. To each sugar is attached a nitrogenous base, only four different kinds of which are commonly found in DNA. Two of these---adenine and guanine--- are purines, and the other two thymine and cytosine-are pyrimidines. A fifth base, 5-methyl cytosine, occurs in smaller amounts in certain organisms, and a sixth, 5-hydroxy-methyl-cytosine, is found instead of cytosine in the T even phages. It should be noted that the chain is unbranched, a consequence of the regular internucleotide linkage. On the other hand the sequence of the different nucleotides is, as far as can be ascertained,completely irregular. Thus, DNA has some features which are regular, and some which are irregular. A similar conception of the DNA molecule as a long thin fiber is obtained from physicochemical analysis involving sedimentation, diffusion, light scattering, and viscosity measurements. These techniques indicate that DNA is a very asymmetrical structure approximately 20 A wide and many thousands of angstroms long. Estimates of its molecular weight currently center between 5 X106and X107(approximately 3 X104nucleotides). Surprisingly each of these measurements tend to suggest that the DNA is relatively rigid, a puzzling finding in view of the large number of single bonds (5 per nucleotid e) in the phosphate-sugar back bone. Recently these indirect inferences have been confirmed by electron microscopy.Q. DNA has a ___________ backbone

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Which of the following is not a characteristic of RNA?

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During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2?.

Solutions for During analysis of the DNA of an organism having 5386 nucleotides find out acst 29% g is equals to 17% c is equals to 32% t is equals to 17% considering that it can be concluded that :1. it is double stranded linear DNA 2.it is double stranded circular DNA 3. it is single stranded DNA 4. both 1 and 2? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

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