A train 200 metres long is moving at the rate of 40 kmph. In how many ...
The correct answer is D as
time = Length of train / speed of train
time = 0.20 km / 40 km/h
time = (0.20 / 40) h
time = 5×10⁻³ h and to convert it to seconds just multiply it by 3600 s/h
time = 5×10⁻³ h * 3600 s/h the unit h is cancelled and the unit seconds remain
time = 18 seconds
View all questions of this testA train 200 metres long is moving at the rate of 40 kmph. In how many ...
Understanding the Problem
To determine how long it takes for a train to cross a stationary man, we need to consider the length of the train and its speed.
Given Data
- Length of the train: 200 meters
- Speed of the train: 40 km/h
Conversion of Speed
First, we need to convert the speed from kilometers per hour to meters per second for easier calculations.
- The formula to convert km/h to m/s is:
Speed (m/s) = Speed (km/h) × (1000 m / 1 km) × (1 hour / 3600 seconds)
Calculating this gives:
- Speed = 40 × (1000 / 3600) = 40 × (5/18) = 11.11 m/s (approximately)
Time Calculation
Now we can calculate the time taken to cross the man:
- Time = Distance / Speed
- Here, the distance is the length of the train, which is 200 meters.
So, we compute:
- Time = 200 m / 11.11 m/s ≈ 18 seconds
Conclusion
Therefore, it takes approximately 18 seconds for the train to completely cross the man standing by the railway line.
The correct answer is option 'D'.
A train 200 metres long is moving at the rate of 40 kmph. In how many ...
The correct answer is D as
time = Length of train / speed of train
time = 0.20 km / 40 km/h
time = (0.20 / 40) h
time = 5×10⁻³ h and to convert it to seconds just multiply it by 3600 s/h
time = 5×10⁻³ h * 3600 s/h the unit h is cancelled and the unit seconds remain
time = 18 seconds