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A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal circle. The maximum tension the string can withstand is 16 Newton. The maximum velocity of revolution that can be given to the stone without breaking it, will be
  • a)
    20 ms⁻1
  • b)
    16 ms⁻1
  • c)
    14 ms⁻1
  • d)
    12 ms⁻1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A stone of mass of 16 kg is attached to a string 144 m long and is whi...
Given:
Mass of stone, m = 16 kg
Length of string, l = 144 m
Maximum tension the string can withstand, T = 16 N

To find:
Maximum velocity of revolution that can be given to the stone without breaking it.

Solution:
Let v be the maximum velocity of revolution that can be given to the stone without breaking it.

Centripetal force required to keep the stone moving in a circle of radius l with velocity v is given by:
Fc = mv²/l

The tension in the string is also acting as a centripetal force and is given by:
T = mv²/l

Equating the above two equations, we get:
mv²/l = T

Substituting the given values, we get:
16 × v²/144 = 16
v² = 144
v = √144
v = 12 m/s

Therefore, the maximum velocity of revolution that can be given to the stone without breaking it is 12 m/s.

Answer: (d) 12 m/s
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A stone of mass of 16 kg is attached to a string 144 m long and is whi...
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A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal circle. The maximum tension the string can withstand is 16 Newton. The maximum velocity of revolution that can be given to the stone without breaking it, will bea)20 ms1b)16 ms1c)14 ms1d)12 ms1Correct answer is option 'D'. Can you explain this answer?
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