These all react with Double bond between C and O and hence eliminate water .. so they can be use for carbonayl detection...!!!

Reaction with hydroxylamine:
Hydroxylamine (NH2OH) reacts with aldehydes and ketones to form oximes. This reaction is commonly known as the oxime formation reaction. The reaction involves the nucleophilic attack of the hydroxylamine nitrogen on the carbonyl carbon, followed by the transfer of the proton from the hydroxyl group to the nitrogen, resulting in the formation of an oxime. This reaction is used for the detection of carbonyl groups because it selectively reacts with aldehydes and ketones, forming a characteristic oxime product.

Reaction with hydrazine:
Hydrazine (N2H4) reacts with aldehydes and ketones to form hydrazones. This reaction is commonly known as the hydrazone formation reaction. The reaction involves the nucleophilic attack of the hydrazine nitrogen on the carbonyl carbon, followed by the transfer of the proton from the hydrazine nitrogen to the oxygen, resulting in the formation of a hydrazone. This reaction is also used for the detection of carbonyl groups because it selectively reacts with aldehydes and ketones, forming a characteristic hydrazone product.

Reaction with phenyl hydrazine:
Phenyl hydrazine (C6H5NHNH2) reacts with aldehydes and ketones to form phenylhydrazones. This reaction is similar to the hydrazone formation reaction and involves the nucleophilic attack of the phenyl hydrazine nitrogen on the carbonyl carbon, followed by the transfer of the proton from the phenyl hydrazine nitrogen to the oxygen, resulting in the formation of a phenylhydrazone. This reaction is also used for the detection of carbonyl groups because it selectively reacts with aldehydes and ketones, forming a characteristic phenylhydrazone product.

Conclusion:
All of the given reactions (reaction with hydroxylamine, reaction with hydrazine, and reaction with phenyl hydrazine) are used for the detection of carbonyl groups. These reactions selectively react with aldehydes and ketones, forming characteristic products (oximes, hydrazones, and phenylhydrazones). Therefore, the correct answer is option D, i.e., all of the above.