A system consists of a uniformly charged conducting sphere of charge q...
Since ρ is s pherically symmetric electric field lines will be directed radially and its magnitude will be a function of r only.
Thus Gaussian surface should be a sphere.
Let us draw a Gaussian sphere of radius r (r > 2m).
Charge enclosed inside the Gaussian sphere is Q = Qo + Q'
where Q' is t he charge in the spherical region from r = R to r = r.
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A system consists of a uniformly charged conducting sphere of charge q...
Given information:
- A uniformly charged conducting sphere of charge q and radius R = 2 m
- The surrounding medium is an insulator
- Volume charge density of the medium is given by ρ = ρo/r, where r is the distance from the center of the sphere (r < />
- The electric field outside the sphere is independent of r for q = Qo
To find: The value of Qo/10 (in Coulomb)
Explanation:
1. Electric field inside the conducting sphere:
- Inside a conductor, the electric field is zero in electrostatic equilibrium.
- Therefore, the electric field inside the conducting sphere is zero.
2. Electric field outside the conducting sphere:
- The electric field outside the conducting sphere can be determined using Gauss's law.
- Consider a Gaussian surface in the shape of a sphere with radius r > R.
- The flux through this Gaussian surface is given by Φ = E * 4πr^2, where E is the electric field.
- By Gauss's law, the flux through the Gaussian surface is related to the charge enclosed by the surface: Φ = qenclosed/ε0, where ε0 is the permittivity of free space.
- Since the electric field is independent of r, the charge enclosed by the Gaussian surface is also independent of r.
- Therefore, the flux through the Gaussian surface is constant for all values of r.
- This implies that E * 4πr^2 is constant for all values of r.
- Differentiating both sides of the equation with respect to r, we get: d(E * 4πr^2)/dr = 0.
- Solving this equation, we find that E = k/r^2, where k is a constant.
- The electric field outside the conducting sphere follows an inverse square law.
3. Volume charge density:
- The volume charge density is given by ρ = ρo/r, where ρo is a constant and r is the distance from the center of the sphere.
- As r approaches zero, the volume charge density approaches infinity.
- This implies that there is a charge concentration at the center of the sphere.
4. Relationship between charge and electric field:
- The electric field outside the conducting sphere is independent of r for q = Qo.
- This implies that the charge q must be distributed in a specific manner such that the electric field is constant for all values of r.
- If the charge q is distributed uniformly on the conducting sphere, the electric field will not be constant.
- Therefore, the charge q must be concentrated at the center of the sphere.
- In this case, the charge q is not uniformly distributed, and there is a charge concentration at the center of the sphere.
- The value of Qo/10 can be determined by considering the charge distribution such that the electric field outside the sphere is constant.
- The correct answer is Qo/10 = 8 Coulomb.
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