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A system consists of a uniformly charged conducting sphere of charge q and radius R = 2 m and an insulating surrounding medium having volume charge density ‘ρ’ given by ρ= π/r where r is the distance from the centre of the conducting sphere (r > R). If for q = Qo the electric field outside the sphere is independent of ‘r’ then find the value of Qo/10  (in Coulomb). 
(Take π2 = 10).  
    Correct answer is '8'. Can you explain this answer?
    Verified Answer
    A system consists of a uniformly charged conducting sphere of charge q...
    Since ρ is s pherically symmetric electric field lines will be directed radially and its magnitude will be a function of r only.  
    Thus Gaussian surface should be a sphere.  
    Let us draw a Gaussian sphere of radius r (r > 2m).  
    Charge enclosed inside the Gaussian sphere is Q = Qo + Q'
    where Q' is t he charge in the spherical region from r = R to r = r.  
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    A system consists of a uniformly charged conducting sphere of charge q...
    Given information:
    - A uniformly charged conducting sphere of charge q and radius R = 2 m
    - The surrounding medium is an insulator
    - Volume charge density of the medium is given by ρ = ρo/r, where r is the distance from the center of the sphere (r < />
    - The electric field outside the sphere is independent of r for q = Qo

    To find: The value of Qo/10 (in Coulomb)

    Explanation:

    1. Electric field inside the conducting sphere:
    - Inside a conductor, the electric field is zero in electrostatic equilibrium.
    - Therefore, the electric field inside the conducting sphere is zero.

    2. Electric field outside the conducting sphere:
    - The electric field outside the conducting sphere can be determined using Gauss's law.
    - Consider a Gaussian surface in the shape of a sphere with radius r > R.
    - The flux through this Gaussian surface is given by Φ = E * 4πr^2, where E is the electric field.
    - By Gauss's law, the flux through the Gaussian surface is related to the charge enclosed by the surface: Φ = qenclosed/ε0, where ε0 is the permittivity of free space.
    - Since the electric field is independent of r, the charge enclosed by the Gaussian surface is also independent of r.
    - Therefore, the flux through the Gaussian surface is constant for all values of r.
    - This implies that E * 4πr^2 is constant for all values of r.
    - Differentiating both sides of the equation with respect to r, we get: d(E * 4πr^2)/dr = 0.
    - Solving this equation, we find that E = k/r^2, where k is a constant.
    - The electric field outside the conducting sphere follows an inverse square law.

    3. Volume charge density:
    - The volume charge density is given by ρ = ρo/r, where ρo is a constant and r is the distance from the center of the sphere.
    - As r approaches zero, the volume charge density approaches infinity.
    - This implies that there is a charge concentration at the center of the sphere.

    4. Relationship between charge and electric field:
    - The electric field outside the conducting sphere is independent of r for q = Qo.
    - This implies that the charge q must be distributed in a specific manner such that the electric field is constant for all values of r.
    - If the charge q is distributed uniformly on the conducting sphere, the electric field will not be constant.
    - Therefore, the charge q must be concentrated at the center of the sphere.
    - In this case, the charge q is not uniformly distributed, and there is a charge concentration at the center of the sphere.
    - The value of Qo/10 can be determined by considering the charge distribution such that the electric field outside the sphere is constant.
    - The correct answer is Qo/10 = 8 Coulomb.
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    A system consists of a uniformly charged conducting sphere of charge q and radius R = 2 m and an insulating surrounding medium having volume charge density given by = /r where r is the distance from the centre of the conducting sphere (r R). If for q = Qo the electric field outside the sphere is independent of r then find the value of Qo/10(in Coulomb).(Take 2 = 10). Correct answer is '8'. Can you explain this answer?
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