We have,
2x+3y-7=0
3kx+2y-1=0
we know,
a1/a2=b1/b2 not equal to c1/c2. has no solution
here, a1= 2, b1=3,
a2=3k, b2=2
thus,
a1/a2=b1/b2
2/3k=3/2
4=9k
so, k=4/9.
thus, the value of k will be 4/9.

Introduction:
In this problem, we are given a pair of linear equations and we need to find the value of k for which the pair of equations has no solution. We will solve the given equations and analyze the conditions for no solution.

Given Equations:
The given pair of linear equations is:
1) 2x + 3y - 7 = 0
2) 3kx + 2y - 1 = 0

Solving the equations:
To find the value of k for which the equations have no solution, we will solve the equations simultaneously.

Step 1: Multiply the first equation by 3k
Multiplying the first equation by 3k, we get:
3k(2x + 3y - 7) = 0
6kx + 9ky - 21k = 0

Step 2: Compare the second equation with the modified first equation
Comparing the second equation with the modified first equation, we get:
6kx + 9ky - 21k = 3kx + 2y - 1

Step 3: Rearrange the equation
Rearranging the equation, we get:
(6kx - 3kx) + (9ky - 2y) - (21k + 1) = 0
(3k - 1)x + (9k - 2)y - (21k + 1) = 0

Step 4: Compare the coefficients of x and y
From the rearranged equation, we can compare the coefficients of x and y:
3k - 1 = 0 (coefficient of x)
9k - 2 = 0 (coefficient of y)

Step 5: Solve the equations
Solving the equations, we get:
3k = 1 --> k = 1/3
9k = 2 --> k = 2/9

Conclusion:
For the given pair of linear equations to have no solution, the value of k should satisfy both equations simultaneously. From our calculations, we find that k = 1/3 and k = 2/9. Therefore, there is no single value of k for which the pair of equations has no solution.