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The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is?
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The energy density in a parallel plate capacitor is given as 2.1*10^-9...
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The energy density in a parallel plate capacitor is given as 2.1*10^-9...
Given:
Energy density (u) = 2.1*10^-9 J/m^3
Find:
Electric field (E) between the plates
Explanation:
Energy Density in a Capacitor:
Energy density (u) in a capacitor is defined as the energy stored per unit volume between the plates of the capacitor.
Relation between Energy Density and Electric Field:
The energy density (u) is related to the electric field (E) by the formula:
u = 0.5 * ε0 * E^2
where ε0 is the permittivity of free space (8.85 x 10^-12 C^2/Nm^2).
Solving for Electric Field:
Given u = 2.1*10^-9 J/m^3
Substitute the values in the formula:
2.1*10^-9 = 0.5 * 8.85*10^-12 * E^2
Solve for E:
E^2 = (2.1*10^-9) / (0.5 * 8.85*10^-12)
E^2 = 0.476271
E = sqrt(0.476271)
E ≈ 0.690 V/m
Conclusion:
The electric field between the plates of the capacitor is approximately 0.690 V/m.
Energy density (u) = 2.1*10^-9 J/m^3
Find:
Electric field (E) between the plates
Explanation:
Energy Density in a Capacitor:
Energy density (u) in a capacitor is defined as the energy stored per unit volume between the plates of the capacitor.
Relation between Energy Density and Electric Field:
The energy density (u) is related to the electric field (E) by the formula:
u = 0.5 * ε0 * E^2
where ε0 is the permittivity of free space (8.85 x 10^-12 C^2/Nm^2).
Solving for Electric Field:
Given u = 2.1*10^-9 J/m^3
Substitute the values in the formula:
2.1*10^-9 = 0.5 * 8.85*10^-12 * E^2
Solve for E:
E^2 = (2.1*10^-9) / (0.5 * 8.85*10^-12)
E^2 = 0.476271
E = sqrt(0.476271)
E ≈ 0.690 V/m
Conclusion:
The electric field between the plates of the capacitor is approximately 0.690 V/m.
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The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is?
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The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is?.
The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy density in a parallel plate capacitor is given as 2.1*10^-9 j/m^3 . The value of the electric field in the region between the plate is?.
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