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Fixation of 1 CO2 requires :–
- a)6NADPH2 & 3ATP
- b)2NADP.H2 & 3ATP
- c)4 NADP.H2 & 3ATP
- d)5 NADP.H2 & 3ATP
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Fixation of 1 CO2 requires :a)6NADPH2 3ATPb)2NADP.H2 3ATPc)4 NADP.H2...
The Calvin cycle has three stages.
1)carbon fixation
2)reduction
3)regeneration.
At the end of each Calvin cycle net gain is 9ATP and 6 NADPH2.In each Calvin cycle, 3 CO2 molecules are fixed with RuBP to form 2 molecules of 3PGA in the first step. Later two molecules of 3PGA through a series of reactions regenerate 2RuBP in the third stage. So, for the fixation of one CO2 carbon dioxide molecule through the Calvin cycle requires 3ATP and 2NADPH2.
So, the correct answer is 'option B'.
1)carbon fixation
2)reduction
3)regeneration.
At the end of each Calvin cycle net gain is 9ATP and 6 NADPH2.In each Calvin cycle, 3 CO2 molecules are fixed with RuBP to form 2 molecules of 3PGA in the first step. Later two molecules of 3PGA through a series of reactions regenerate 2RuBP in the third stage. So, for the fixation of one CO2 carbon dioxide molecule through the Calvin cycle requires 3ATP and 2NADPH2.
So, the correct answer is 'option B'.
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Community Answer
Fixation of 1 CO2 requires :a)6NADPH2 3ATPb)2NADP.H2 3ATPc)4 NADP.H2...
The carbon dioxide acceptor in Calvin cycle is ribulose 1,5-biphosphate and the first product is 3-phosphoglyceric acid. This conversion is catalyzed by the RUBISCO. Since the first stable product is the three carbon compound, it is called C3 cycle. When 6 molecules of carbon dioxide enter Calvin cycle, one hexose molecule is formed. 18 ATP and 12 NADPH2 molecules are used up.
Thus, the ATP and NADPH2 consumed per carbon atom fixed in glucose are 3 ATP and 2 NADPH2...
So, correct answer is option (B)...
$$Hope it's help... $$
Thus, the ATP and NADPH2 consumed per carbon atom fixed in glucose are 3 ATP and 2 NADPH2...
So, correct answer is option (B)...
$$Hope it's help... $$
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