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The solubility product expression for silver(I) sulphide, using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, is formulated as:
- a)x2y2
- b)xy3
- c)x2y
- d)xy2
Correct answer is option 'C'. Can you explain this answer?
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The solubility product expression for silver(I) sulphide, using x to r...
The correct answer is Option C.
The ionization equilibrium of silver (I) sulfide is
Ag2S⇌2Ag+ +S2−
The solubility product expression for silver (I) sulfide is KSP[Ag+]2 [S2−].
But [Ag+]2 = x and [S2−] = y.
Hence the expression for the solubility product becomes KSP[Ag+]2 [S2−] = x2y.
The ionization equilibrium of silver (I) sulfide is
Ag2S⇌2Ag+ +S2−
The solubility product expression for silver (I) sulfide is KSP[Ag+]2 [S2−].
But [Ag+]2 = x and [S2−] = y.
Hence the expression for the solubility product becomes KSP[Ag+]2 [S2−] = x2y.
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The solubility product expression for silver(I) sulphide, using x to r...
Solubility product expression for silver(I) sulphide
The solubility product expression for silver(I) sulphide is given by:
Ag2S ⇌ 2Ag+ + S2-
Ksp = [Ag+]2 [S2-]
where Ksp is the solubility product constant.
Formulation of solubility product expression
Using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, the solubility product expression can be formulated as:
Ag2S ⇌ 2Ag+ + S2-
Ksp = [Ag+]2 [S2-]
[Ag+] = 2x (since 2 moles of Ag+ are formed for every mole of Ag2S)
[S2-] = y (since 1 mole of S2- is formed for every mole of Ag2S)
Substituting the values of [Ag+] and [S2-] in the solubility product expression, we get:
Ksp = (2x)2 y
Simplifying the expression, we get:
Ksp = 4x2y
Therefore, the correct option is C) x2y.
The solubility product expression for silver(I) sulphide is given by:
Ag2S ⇌ 2Ag+ + S2-
Ksp = [Ag+]2 [S2-]
where Ksp is the solubility product constant.
Formulation of solubility product expression
Using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, the solubility product expression can be formulated as:
Ag2S ⇌ 2Ag+ + S2-
Ksp = [Ag+]2 [S2-]
[Ag+] = 2x (since 2 moles of Ag+ are formed for every mole of Ag2S)
[S2-] = y (since 1 mole of S2- is formed for every mole of Ag2S)
Substituting the values of [Ag+] and [S2-] in the solubility product expression, we get:
Ksp = (2x)2 y
Simplifying the expression, we get:
Ksp = 4x2y
Therefore, the correct option is C) x2y.
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The solubility product expression for silver(I) sulphide, using x to represent the molar concentration of silver(I) and y to represent the molar concentration of sulphide, is formulated as:a)x2y2b)xy3c)x2yd)xy2Correct answer is option 'C'. Can you explain this answer?
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