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A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod?
Most Upvoted Answer
A graduated uniform metre rod is balanced horizontally on a knife edge...
Given:
- Distance of the knife edge from the center of gravity = 10 cm
- Mass suspended at the 5 cm division of the rod = 50 g
- Mass suspended at the 90 cm division of the rod = 30 g
To Find:
- Weight of the rod
Explanation:
To find the weight of the rod, we need to consider the moments acting on the rod.
1. Moment due to the weight of the rod:
The weight of the rod acts at its center of gravity, which is the midpoint.
Weight of the rod = Mass of the rod × Acceleration due to gravity
2. Moment due to the mass suspended at the 5 cm division:
The moment due to the mass suspended at the 5 cm division is given by the product of the mass and the distance from the knife edge.
Moment due to the 50 g mass = (50 g) × (5 cm)
3. Moment due to the mass suspended at the 90 cm division:
The moment due to the mass suspended at the 90 cm division is given by the product of the mass and the distance from the knife edge.
Moment due to the 30 g mass = (30 g) × (90 cm)
4. Balancing condition:
For the rod to be balanced horizontally, the sum of the anti-clockwise moments must be equal to the sum of the clockwise moments.
Sum of anti-clockwise moments = Moment due to the 50 g mass
Sum of clockwise moments = Moment due to the 30 g mass + Moment due to the weight of the rod
5. Calculating the weight of the rod:
By equating the sums of the moments, we can find the weight of the rod.
Moment due to the weight of the rod = Sum of anti-clockwise moments - Sum of clockwise moments
Weight of the rod = (Moment due to the 50 g mass) - (Moment due to the 30 g mass)
Substituting the given values:
- Mass of the rod = Weight of the rod / Acceleration due to gravity
- Acceleration due to gravity = 9.8 m/s²
Conclusion:
By substituting the given values into the equation, we can calculate the weight of the rod.
- Distance of the knife edge from the center of gravity = 10 cm
- Mass suspended at the 5 cm division of the rod = 50 g
- Mass suspended at the 90 cm division of the rod = 30 g
To Find:
- Weight of the rod
Explanation:
To find the weight of the rod, we need to consider the moments acting on the rod.
1. Moment due to the weight of the rod:
The weight of the rod acts at its center of gravity, which is the midpoint.
Weight of the rod = Mass of the rod × Acceleration due to gravity
2. Moment due to the mass suspended at the 5 cm division:
The moment due to the mass suspended at the 5 cm division is given by the product of the mass and the distance from the knife edge.
Moment due to the 50 g mass = (50 g) × (5 cm)
3. Moment due to the mass suspended at the 90 cm division:
The moment due to the mass suspended at the 90 cm division is given by the product of the mass and the distance from the knife edge.
Moment due to the 30 g mass = (30 g) × (90 cm)
4. Balancing condition:
For the rod to be balanced horizontally, the sum of the anti-clockwise moments must be equal to the sum of the clockwise moments.
Sum of anti-clockwise moments = Moment due to the 50 g mass
Sum of clockwise moments = Moment due to the 30 g mass + Moment due to the weight of the rod
5. Calculating the weight of the rod:
By equating the sums of the moments, we can find the weight of the rod.
Moment due to the weight of the rod = Sum of anti-clockwise moments - Sum of clockwise moments
Weight of the rod = (Moment due to the 50 g mass) - (Moment due to the 30 g mass)
Substituting the given values:
- Mass of the rod = Weight of the rod / Acceleration due to gravity
- Acceleration due to gravity = 9.8 m/s²
Conclusion:
By substituting the given values into the equation, we can calculate the weight of the rod.
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A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod?
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A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod?.
A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A graduated uniform metre rod is balanced horizontally on a knife edge at a distance of 10cm from the centre of gravity, when masses of 50g and 30g are suspended at the 5cm and 90cm division of the rod. Find the weight of the rod?.
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