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Paragraph For Question No.12 and 13
A white compound (A) on strong heating decomposes to produce two products (B) and (C). (B) on reaction with white phosphorus produces (D), which is a strong dehydrating agent. (D) on reaction with perchloric acid converts it to its anhydride.
The product/s obtained on hydrolysis of (D) is
 
 
  • a)
    Mixture of H3PO3 and H3PO4
  • b)
    only PH3
  • c)
    only H3PO3
  • d)
    Mixture of H3PO3 and H3PO2
Correct answer is option 'C'. Can you explain this answer?
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Paragraph For Question No.12 and 13A white compound (A) on strong heat...
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Paragraph For Question No.12 and 13A white compound (A) on strong heat...
Answer:



Decomposition of Compound A:


When compound A is strongly heated, it decomposes into two products, B and C. The reaction can be represented as follows:

A → B + C

Reaction of Compound B with White Phosphorus:


Compound B reacts with white phosphorus (P4) to form compound D, which is a strong dehydrating agent. The reaction can be represented as follows:

B + P4 → D

Reaction of Compound D with Perchloric Acid:


Compound D reacts with perchloric acid to convert it to its anhydride. The reaction can be represented as follows:

D + HClO4 → Anhydride

Hydrolysis of Compound D:


The product obtained on hydrolysis of compound D can be determined by analyzing the reaction and the properties of the compounds involved.

Compound D is a strong dehydrating agent, which means it has the ability to remove water molecules. In the presence of water, compound D will react to form various products, including phosphorous acid (H3PO3) and phosphoric acid (H3PO4).

The reaction can be represented as follows:

D + H2O → H3PO3 + H3PO4

Conclusion:


Based on the reaction and properties of compound D, the product obtained on hydrolysis of compound D is a mixture of phosphorous acid (H3PO3) and phosphoric acid (H3PO4). Therefore, the correct answer is option C, "only H3PO3".
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Paragraph For Question No.12 and 13A white compound (A) on strong heating decomposes to produce two products (B) and (C). (B) on reaction with white phosphorus produces (D), which is a strong dehydrating agent. (D) on reaction with perchloric acid converts it to its anhydride.The product/s obtained on hydrolysis of (D) isa)Mixture of H3PO3 and H3PO4b)only PH3c)only H3PO3d)Mixture of H3PO3 and H3PO2Correct answer is option 'C'. Can you explain this answer?
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Paragraph For Question No.12 and 13A white compound (A) on strong heating decomposes to produce two products (B) and (C). (B) on reaction with white phosphorus produces (D), which is a strong dehydrating agent. (D) on reaction with perchloric acid converts it to its anhydride.The product/s obtained on hydrolysis of (D) isa)Mixture of H3PO3 and H3PO4b)only PH3c)only H3PO3d)Mixture of H3PO3 and H3PO2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Paragraph For Question No.12 and 13A white compound (A) on strong heating decomposes to produce two products (B) and (C). (B) on reaction with white phosphorus produces (D), which is a strong dehydrating agent. (D) on reaction with perchloric acid converts it to its anhydride.The product/s obtained on hydrolysis of (D) isa)Mixture of H3PO3 and H3PO4b)only PH3c)only H3PO3d)Mixture of H3PO3 and H3PO2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Paragraph For Question No.12 and 13A white compound (A) on strong heating decomposes to produce two products (B) and (C). (B) on reaction with white phosphorus produces (D), which is a strong dehydrating agent. (D) on reaction with perchloric acid converts it to its anhydride.The product/s obtained on hydrolysis of (D) isa)Mixture of H3PO3 and H3PO4b)only PH3c)only H3PO3d)Mixture of H3PO3 and H3PO2Correct answer is option 'C'. Can you explain this answer?.
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