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Let z be a complex number satisfying z2 + 2αz + 1 = 0 where α is a parameter which can take any real value.
The roots of this equation lie on a certain circle if
  • a)
    -1<α<1
  • b)
    α >1
  • c)
     α <1
  • d)
    none of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Let z be a complex number satisfying z2 + 2αz + 1 = 0 where &alp...
one root lies inside the unit circle and other will outside the unit circle case||| where α is very large then
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Let z be a complex number satisfying z2 + 2αz + 1 = 0 where α is a parameter which can take any real value.The roots of this equation lie on a certain circle ifa)-1<α<1b)α >1c)α <1d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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Let z be a complex number satisfying z2 + 2αz + 1 = 0 where α is a parameter which can take any real value.The roots of this equation lie on a certain circle ifa)-1<α<1b)α >1c)α <1d)none of theseCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let z be a complex number satisfying z2 + 2αz + 1 = 0 where α is a parameter which can take any real value.The roots of this equation lie on a certain circle ifa)-1<α<1b)α >1c)α <1d)none of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let z be a complex number satisfying z2 + 2αz + 1 = 0 where α is a parameter which can take any real value.The roots of this equation lie on a certain circle ifa)-1<α<1b)α >1c)α <1d)none of theseCorrect answer is option 'A'. Can you explain this answer?.
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