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How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g?
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How much mass of silver nitrate will react with 5.85 g of sodium chlor...
- **Given Data:**
- Mass of sodium chloride (NaCl) = 5.85g
- Mass of silver chloride (AgCl) produced = 14.35g
- Mass of sodium nitrate (NaNO3) produced = 8.5g
- **Balanced Chemical Equation:**
- AgNO3 + NaCl → AgCl + NaNO3
- **Step 1: Calculate the molar mass of each compound:**
- Molar mass of AgNO3 = 169.87 g/mol
- Molar mass of NaCl = 58.44 g/mol
- Molar mass of AgCl = 143.32 g/mol
- Molar mass of NaNO3 = 84.99 g/mol
- **Step 2: Calculate the moles of AgCl and NaNO3 produced:**
- Moles of AgCl = Mass / Molar mass = 14.35g / 143.32 g/mol = 0.1 mol
- Moles of NaNO3 = Mass / Molar mass = 8.5g / 84.99 g/mol = 0.1 mol
- **Step 3: Determine the limiting reactant:**
- Calculate the moles of NaCl using its molar mass:
- Moles of NaCl = 5.85g / 58.44 g/mol = 0.1 mol
- Since the moles of NaCl and AgCl are equal, NaCl is the limiting reactant.
- **Step 4: Calculate the mass of AgNO3 required to react with NaCl:**
- Mass of AgNO3 = Moles of NaCl * Molar mass of NaCl = 0.1 mol * 169.87 g/mol = 16.987g
- **Step 5: Calculate the mass of AgNO3 that will react with NaCl:**
- Since the mass of AgNO3 required is 16.987g, and the total mass of AgNO3 produced is 14.35g, the mass of AgNO3 that will react with NaCl is 14.35g.
- **Final Answer:**
- The mass of silver nitrate that will react with 5.85g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate is 14.35g.
Therefore, the correct answer is **C) 17.0g**.
- Mass of sodium chloride (NaCl) = 5.85g
- Mass of silver chloride (AgCl) produced = 14.35g
- Mass of sodium nitrate (NaNO3) produced = 8.5g
- **Balanced Chemical Equation:**
- AgNO3 + NaCl → AgCl + NaNO3
- **Step 1: Calculate the molar mass of each compound:**
- Molar mass of AgNO3 = 169.87 g/mol
- Molar mass of NaCl = 58.44 g/mol
- Molar mass of AgCl = 143.32 g/mol
- Molar mass of NaNO3 = 84.99 g/mol
- **Step 2: Calculate the moles of AgCl and NaNO3 produced:**
- Moles of AgCl = Mass / Molar mass = 14.35g / 143.32 g/mol = 0.1 mol
- Moles of NaNO3 = Mass / Molar mass = 8.5g / 84.99 g/mol = 0.1 mol
- **Step 3: Determine the limiting reactant:**
- Calculate the moles of NaCl using its molar mass:
- Moles of NaCl = 5.85g / 58.44 g/mol = 0.1 mol
- Since the moles of NaCl and AgCl are equal, NaCl is the limiting reactant.
- **Step 4: Calculate the mass of AgNO3 required to react with NaCl:**
- Mass of AgNO3 = Moles of NaCl * Molar mass of NaCl = 0.1 mol * 169.87 g/mol = 16.987g
- **Step 5: Calculate the mass of AgNO3 that will react with NaCl:**
- Since the mass of AgNO3 required is 16.987g, and the total mass of AgNO3 produced is 14.35g, the mass of AgNO3 that will react with NaCl is 14.35g.
- **Final Answer:**
- The mass of silver nitrate that will react with 5.85g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate is 14.35g.
Therefore, the correct answer is **C) 17.0g**.
Community Answer
How much mass of silver nitrate will react with 5.85 g of sodium chlor...
C) 17.0g
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How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g?
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How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g?.
How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35g of silver chloride and 8.5g of sodium nitrate if law of conservation of mass is followed? A)22.85g B) 108g C)17.0 g D)28.70g?.
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