Class 11 Exam > Class 11 Questions > Passage I A number of unsaturated hydrocarbon...
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Passage I
A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.
Q.
How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?
Q.
How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?
- a)3
- b)4
- c)5
- d)6
Correct answer is option 'C'. Can you explain this answer?
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Passage I A number of unsaturated hydrocarbons have the same molecular...
Explanation:
Geometrical isomerism occurs in unsaturated hydrocarbons that have a double bond between two carbon atoms. The double bond restricts the rotation around the carbon-carbon bond, and therefore, the atoms or groups attached to the double bond can be arranged in different ways, resulting in different isomers.
Given that all unsaturated hydrocarbons with molecular formula C11H22 give the same product on catalytic hydrogenation, it means they all have the same number and arrangement of carbon and hydrogen atoms. Therefore, the differences in the number and position of double bonds are responsible for the isomerism.
To determine the number of unsaturated hydrocarbons capable of exhibiting geometrical isomerism, we need to consider the possible arrangements of double bonds in a chain of 11 carbon atoms.
Possible double bond arrangements:
1. One double bond: This would result in a C=C bond between two adjacent carbon atoms, leaving nine carbon atoms to attach hydrogen atoms. There are no other possible isomers.
2. Two double bonds: This would result in a C=C bond between every other pair of carbon atoms, leaving seven carbon atoms to attach hydrogen atoms. There are two possible isomers: 3-methyl-1,5-octadiene and 2-methyl-1,6-octadiene.
3. Three double bonds: This would result in a C=C bond between every third pair of carbon atoms, leaving five carbon atoms to attach hydrogen atoms. There are three possible isomers: 3,5-dimethyl-1,4-octadiene, 2,6-dimethyl-1,5-octadiene, and 2,4-dimethyl-1,6-octadiene.
Therefore, there are five unsaturated hydrocarbons capable of exhibiting geometrical isomerism.
Answer: c) 5
Geometrical isomerism occurs in unsaturated hydrocarbons that have a double bond between two carbon atoms. The double bond restricts the rotation around the carbon-carbon bond, and therefore, the atoms or groups attached to the double bond can be arranged in different ways, resulting in different isomers.
Given that all unsaturated hydrocarbons with molecular formula C11H22 give the same product on catalytic hydrogenation, it means they all have the same number and arrangement of carbon and hydrogen atoms. Therefore, the differences in the number and position of double bonds are responsible for the isomerism.
To determine the number of unsaturated hydrocarbons capable of exhibiting geometrical isomerism, we need to consider the possible arrangements of double bonds in a chain of 11 carbon atoms.
Possible double bond arrangements:
1. One double bond: This would result in a C=C bond between two adjacent carbon atoms, leaving nine carbon atoms to attach hydrogen atoms. There are no other possible isomers.
2. Two double bonds: This would result in a C=C bond between every other pair of carbon atoms, leaving seven carbon atoms to attach hydrogen atoms. There are two possible isomers: 3-methyl-1,5-octadiene and 2-methyl-1,6-octadiene.
3. Three double bonds: This would result in a C=C bond between every third pair of carbon atoms, leaving five carbon atoms to attach hydrogen atoms. There are three possible isomers: 3,5-dimethyl-1,4-octadiene, 2,6-dimethyl-1,5-octadiene, and 2,4-dimethyl-1,6-octadiene.
Therefore, there are five unsaturated hydrocarbons capable of exhibiting geometrical isomerism.
Answer: c) 5
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Passage I A number of unsaturated hydrocarbons have the same molecular...
C is correct.
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Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?
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Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?.
Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?.
Solutions for Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Passage I A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane.Q.How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism?a)3b)4c)5d)6Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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