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The minimum mass of mixture of A2 and B4
required to produce at least 1 kg of each product is :
(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)
5A2 + 2B4 2AB2 + 4A2B
(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm?
required to produce at least 1 kg of each product is :
(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)
5A2 + 2B4 2AB2 + 4A2B
(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm?
Most Upvoted Answer
The minimum mass of mixture of A2 and B4required to produce at least 1...
To determine the minimum mass of the mixture of A2 and B4 required to produce at least 1 kg of each product, we need to consider the stoichiometry of the reaction and the molar masses of A2 and B4.
Given:
Atomic mass of A (A2) = 10 g/mol
Atomic mass of B (B4) = 120 g/mol
Step 1: Determine the molar masses of the products
- AB2: 2 atoms of A and 1 atom of B = 2(10 g/mol) + 1(120 g/mol) = 140 g/mol
- A2B4: 4 atoms of A and 1 atom of B = 4(10 g/mol) + 1(120 g/mol) = 160 g/mol
Step 2: Calculate the minimum mass of the mixture required
Since the reaction produces 2 moles of AB2 and 4 moles of A2B4, we need to find the mass of the mixture that contains at least 1 kg (1000 g) of each product.
For AB2:
- 2 moles of AB2 = 2(140 g/mol) = 280 g
For A2B4:
- 4 moles of A2B4 = 4(160 g/mol) = 640 g
Therefore, the total mass of the mixture needed is:
- 280 g + 640 g = 920 g
However, this mass is less than 1000 g, which means it does not fulfill the requirement of producing at least 1 kg of each product.
Step 3: Calculate the additional mass needed
To meet the requirement, we need to calculate the additional mass needed to make the total mass of the mixture at least 1000 g.
Additional mass needed = 1000 g - 920 g = 80 g
Therefore, the minimum mass of the mixture of A2 and B4 required to produce at least 1 kg of each product is:
920 g + 80 g = 1000 g
Answer:
The correct option is (A) 2120 g.
Given:
Atomic mass of A (A2) = 10 g/mol
Atomic mass of B (B4) = 120 g/mol
Step 1: Determine the molar masses of the products
- AB2: 2 atoms of A and 1 atom of B = 2(10 g/mol) + 1(120 g/mol) = 140 g/mol
- A2B4: 4 atoms of A and 1 atom of B = 4(10 g/mol) + 1(120 g/mol) = 160 g/mol
Step 2: Calculate the minimum mass of the mixture required
Since the reaction produces 2 moles of AB2 and 4 moles of A2B4, we need to find the mass of the mixture that contains at least 1 kg (1000 g) of each product.
For AB2:
- 2 moles of AB2 = 2(140 g/mol) = 280 g
For A2B4:
- 4 moles of A2B4 = 4(160 g/mol) = 640 g
Therefore, the total mass of the mixture needed is:
- 280 g + 640 g = 920 g
However, this mass is less than 1000 g, which means it does not fulfill the requirement of producing at least 1 kg of each product.
Step 3: Calculate the additional mass needed
To meet the requirement, we need to calculate the additional mass needed to make the total mass of the mixture at least 1000 g.
Additional mass needed = 1000 g - 920 g = 80 g
Therefore, the minimum mass of the mixture of A2 and B4 required to produce at least 1 kg of each product is:
920 g + 80 g = 1000 g
Answer:
The correct option is (A) 2120 g.
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The minimum mass of mixture of A2 and B4required to produce at least 1 kg of each product is :(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)5A2 + 2B4 2AB2 + 4A2B(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm?
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The minimum mass of mixture of A2 and B4required to produce at least 1 kg of each product is :(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)5A2 + 2B4 2AB2 + 4A2B(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The minimum mass of mixture of A2 and B4required to produce at least 1 kg of each product is :(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)5A2 + 2B4 2AB2 + 4A2B(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum mass of mixture of A2 and B4required to produce at least 1 kg of each product is :(Given At. mass of 'A' = 10 ; At. mass of 'B' = 120)5A2 + 2B4 2AB2 + 4A2B(A) 2120 gm (B) 1060 gm (C) 560 gm (D) 1660 gm?.
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