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The force between two charges is 120 N. If the distance between the charges is doubled, the force will be
- a)60 N
- b)30 N
- c)40 N
- d)15 N
Correct answer is option 'B'. Can you explain this answer?
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The force between two charges is 120 N. If the distance between the ch...
Coulombs law states the force between two charged particles is directly proportional to the product of charges and inversely proportional to the square of distance between them.
So if the distance is doubled then the force would decrease 4 times.
So the new force would be 120/4=30 Newton.
So if the distance is doubled then the force would decrease 4 times.
So the new force would be 120/4=30 Newton.
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The force between two charges is 120 N. If the distance between the ch...
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The force between two charges is 120 N. If the distance between the ch...
Given:
Force between two charges = 120 N
Distance between the charges = d
To find:
Force when distance is doubled
Explanation:
Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be represented as:
F = k * q1 * q2 / d^2
where F is the force, q1 and q2 are the charges, d is the distance between them, and k is the Coulomb's constant.
Now, let's consider the given scenario where the distance between the charges is doubled. Let the new distance be 2d.
From Coulomb's law, we know that the force is inversely proportional to the square of the distance. Therefore,
F' = k * q1 * q2 / (2d)^2
F' = k * q1 * q2 / 4d^2
F' = F / 4
So, the new force is 1/4th of the original force.
Substituting the given values, we get:
F' = 120 N / 4
F' = 30 N
Therefore, the force when the distance is doubled is 30 N.
Answer: Option B (30 N)
Force between two charges = 120 N
Distance between the charges = d
To find:
Force when distance is doubled
Explanation:
Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be represented as:
F = k * q1 * q2 / d^2
where F is the force, q1 and q2 are the charges, d is the distance between them, and k is the Coulomb's constant.
Now, let's consider the given scenario where the distance between the charges is doubled. Let the new distance be 2d.
From Coulomb's law, we know that the force is inversely proportional to the square of the distance. Therefore,
F' = k * q1 * q2 / (2d)^2
F' = k * q1 * q2 / 4d^2
F' = F / 4
So, the new force is 1/4th of the original force.
Substituting the given values, we get:
F' = 120 N / 4
F' = 30 N
Therefore, the force when the distance is doubled is 30 N.
Answer: Option B (30 N)
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The force between two charges is 120 N. If the distance between the charges is doubled, the force will bea)60 Nb)30 Nc)40 Nd)15 NCorrect answer is option 'B'. Can you explain this answer?
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