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A ballon is rising vertically up with a velocity of 29 ms-1.A stone is dropped form it and it reaches the ground in10s. The height of the balloon when the stone wasdropped from it is (g = 9.8 ms-2)
- a)400 m
- b)150 m
- c)100 m
- d)200 m
Correct answer is option 'D'. Can you explain this answer?
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A ballon is rising vertically up with a velocity of 29 ms-1.A stone is...
Given:
Velocity of the balloon, u = 29 ms-1
Time taken by the stone to reach the ground, t = 10s
Acceleration due to gravity, g = 9.8 ms-2
We need to find the height of the balloon when the stone was dropped from it.
Let's assume that the height of the balloon when the stone was dropped is h. At that instant, the velocity of the stone is zero.
Using the equation of motion, we can find the height of the balloon:
h = ut + (1/2)gt^2
Substituting the values, we get:
h = 29 x 10 + (1/2) x 9.8 x (10)^2
h = 290 + 490
h = 780m
Therefore, the height of the balloon when the stone was dropped from it is 780m. However, this is not the final answer because we need to find the height of the balloon above the ground level.
Let's assume that the height of the balloon above the ground level is H. At that instant, the velocity of the stone is u.
Using the equation of motion, we can find the height of the balloon above the ground level:
H = ut - (1/2)gt^2
Substituting the values, we get:
H = 29 x 10 - (1/2) x 9.8 x (10)^2
H = 290 - 490
H = -200m
Since the height cannot be negative, we take the absolute value of H, which is 200m.
Therefore, the height of the balloon above the ground level when the stone was dropped from it is 200m. Hence, the correct option is D) 200m.
Velocity of the balloon, u = 29 ms-1
Time taken by the stone to reach the ground, t = 10s
Acceleration due to gravity, g = 9.8 ms-2
We need to find the height of the balloon when the stone was dropped from it.
Let's assume that the height of the balloon when the stone was dropped is h. At that instant, the velocity of the stone is zero.
Using the equation of motion, we can find the height of the balloon:
h = ut + (1/2)gt^2
Substituting the values, we get:
h = 29 x 10 + (1/2) x 9.8 x (10)^2
h = 290 + 490
h = 780m
Therefore, the height of the balloon when the stone was dropped from it is 780m. However, this is not the final answer because we need to find the height of the balloon above the ground level.
Let's assume that the height of the balloon above the ground level is H. At that instant, the velocity of the stone is u.
Using the equation of motion, we can find the height of the balloon above the ground level:
H = ut - (1/2)gt^2
Substituting the values, we get:
H = 29 x 10 - (1/2) x 9.8 x (10)^2
H = 290 - 490
H = -200m
Since the height cannot be negative, we take the absolute value of H, which is 200m.
Therefore, the height of the balloon above the ground level when the stone was dropped from it is 200m. Hence, the correct option is D) 200m.
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A ballon is rising vertically up with a velocity of 29 ms-1.A stone is dropped form it and it reaches the ground in10s. The height of the balloon when the stone wasdropped from it is (g = 9.8 ms-2)a)400 mb)150 mc)100 md)200 mCorrect answer is option 'D'. Can you explain this answer?
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