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A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will be
- a)130 N
- b)120 N
- c)150N
- d)115 N
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The...
The force of friction road/tire is what is propelling the forward motion. If this is a 100% efficient machine, then the answer is 250N. If there are losses due to friction inside the bicycle, it is less than that. If the bicycle is negligible mass, then the force is 30x4 = 120 N.
This question is part of UPSC exam. View all Class 11 courses
Most Upvoted Answer
A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The...
-2.
To solve this problem, we can use the equation:
force = mass x acceleration
where force is given as 250 N, mass is given as 30 kg, and acceleration is what we're trying to find.
Substituting the values, we get:
250 N = 30 kg x acceleration
Solving for acceleration, we get:
acceleration = 250 N / 30 kg
acceleration = 8.33 ms-2
However, this is not the correct answer as we were given that the acceleration is 4 ms-2.
Therefore, we can conclude that there is some external force acting on the cyclist and his cycle that is opposing the applied force of 250 N, resulting in a lower acceleration of 4 ms-2.
To solve this problem, we can use the equation:
force = mass x acceleration
where force is given as 250 N, mass is given as 30 kg, and acceleration is what we're trying to find.
Substituting the values, we get:
250 N = 30 kg x acceleration
Solving for acceleration, we get:
acceleration = 250 N / 30 kg
acceleration = 8.33 ms-2
However, this is not the correct answer as we were given that the acceleration is 4 ms-2.
Therefore, we can conclude that there is some external force acting on the cyclist and his cycle that is opposing the applied force of 250 N, resulting in a lower acceleration of 4 ms-2.
Community Answer
A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The...
F=ma'
a'=250/30
a'=8.3
a'>a
then
Fr=ma=30×4
Fr=120N
a'=250/30
a'=8.3
a'>a
then
Fr=ma=30×4
Fr=120N
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A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?
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A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?.
A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)130 Nb)120 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?.
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