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The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibb's energy change (ΔG).
ΔG = ΔH – TΔS
where,        ΔH = Enthalpy change ; ΔS = Entropy change;
                  T = Temperature in kelvin.
If ΔG < 0, Process is spontaneous ; ΔG = 0, Process is at equilibrium, AG > 0, Process is non-spontaneous.
Q.
Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.
CaC03 (s) → CaO (s) + C02 (g), (ΔH°) = 180 KJ, ΔS° = 150 J/K.
Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :
  • a)
    Decomposition of CaCO3 (s) is never spontaneous.
  • b)
    Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900°C.
  • c)
    Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000°C
  • d)
    Decomposition of CaCO3(s) becomes spontaneous whentemperature is  greater than 927°C.
Correct answer is option 'D'. Can you explain this answer?
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The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer?
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The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer?.
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When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. 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When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If G 0, Process is spontaneous ; G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
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