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The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer?.
Solutions for The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The contributions of both heat (enthalpy) and randomness (entropy) shall be considered to the overall spontaneity of a process. When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibbs energy change (G).G = H TSwhere,H = Enthalpy change ; S = Entropy change;T = Temperature in kelvin.If
G 0, Process is spontaneous ;
G = 0, Process is at equilibrium, AG 0, Process is non-spontaneous.Q.Quick lime, Ca0 is produced by heating limestone, CaC03 to drive off C02 gas.CaC03 (s) CaO (s) + C02 (g), (H) = 180 KJ, S = 150 J/K.Assuming that variation of enthalpy change and entropy change with temperature to be negligible, choose the correct option :a)Decomposition of CaCO3 (s) is never spontaneous.b)Decomposition of CaCO3 (s)becomes spontaneous when temperature is less than 900C.c)Decomposition of CaC03 (s) becomes non-spontaneous when temperature is greater than 1000Cd)Decomposition of CaCO3(s) becomes spontaneous whentemperature is greater than 927C.Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.