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In the formula , p = (nRT)/(V-b) e ^(a)/(RTV) find the dimensions of a and b, where p = pressure , n= number of moles , T = temperture , V = volume and E = universal gas constant .answer plz?
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Dimensions of a and b in the Formula

The given formula is:

p = (nRT)/(V-b) e ^(a)/(RTV)

Here, we need to find the dimensions of a and b.

Dimension of a:

To find the dimension of a, we can use the exponential term in the given formula:

e ^(a)/(RTV)

The exponential term is dimensionless, so we can equate the dimensions of the numerator and denominator:

Dimension of a = Dimension of RTV

Now, let's break down the dimensions of RTV:

Dimension of R = [M L^2 T^-2 K^-1]

Dimension of T = [T]

Dimension of V = [L^3]

So, the dimension of RTV is:

[M L^2 T^-2 K^-1] [T] [L^3] = [M L^5 T^-2 K^-1]

Therefore, the dimension of a is also [M L^5 T^-2 K^-1].

Dimension of b:

To find the dimension of b, we can look at the denominator of the given formula:

V-b

The dimension of V is [L^3]. To make the units consistent, the dimension of b must also be [L^3]. Therefore, the dimension of b is [L^3].

Conclusion:

- The dimension of a in the given formula is [M L^5 T^-2 K^-1].
- The dimension of b in the given formula is [L^3].
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In the formula , p = (nRT)/(V-b) e ^(a)/(RTV) find the dimensions of a and b, where p = pressure , n= number of moles , T = temperture , V = volume and E = universal gas constant .answer plz?
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