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Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is?
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Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with ...
Calculating the Smallest Distance between the Centres of Two C60 Molecules in Fullerene
To calculate the smallest distance between the centres of two C60 molecules in Fullerene, we need to follow these steps:
1. Determine the number of lattice points in an fcc unit cell.
2. Calculate the distance between adjacent lattice points.
3. Determine the distance between the centres of two C60 molecules.
4. Compare the distances calculated in steps 2 and 3 to find the smallest distance.
Step 1: Determine the Number of Lattice Points in an FCC Unit Cell
An FCC unit cell has 4 lattice points - one at each corner of the cube and one at the centre of each of the 6 faces.
Step 2: Calculate the Distance between Adjacent Lattice Points
The edge length of the FCC unit cell is given as 14.14 Å. The distance between adjacent lattice points can be calculated using the formula:
d = a/√2
where 'a' is the edge length of the unit cell.
Substituting the values, we get:
d = 14.14/√2
= 9.998 Å (approx.)
Step 3: Determine the Distance between the Centres of Two C60 Molecules
Since each C60 molecule is centred at a lattice point, the distance between the centres of two C60 molecules can be calculated as the distance between two adjacent lattice points, which we calculated in Step 2.
Therefore, the distance between the centres of two C60 molecules is approximately 9.998 Å.
Step 4: Compare the Distances from Steps 2 and 3
Comparing the distances calculated in Steps 2 and 3, we see that the distance between the centres of two C60 molecules is the smallest distance.
Therefore, the smallest distance between the centres of two C60 molecules in Fullerene is approximately 9.998 Å.
To calculate the smallest distance between the centres of two C60 molecules in Fullerene, we need to follow these steps:
1. Determine the number of lattice points in an fcc unit cell.
2. Calculate the distance between adjacent lattice points.
3. Determine the distance between the centres of two C60 molecules.
4. Compare the distances calculated in steps 2 and 3 to find the smallest distance.
Step 1: Determine the Number of Lattice Points in an FCC Unit Cell
An FCC unit cell has 4 lattice points - one at each corner of the cube and one at the centre of each of the 6 faces.
Step 2: Calculate the Distance between Adjacent Lattice Points
The edge length of the FCC unit cell is given as 14.14 Å. The distance between adjacent lattice points can be calculated using the formula:
d = a/√2
where 'a' is the edge length of the unit cell.
Substituting the values, we get:
d = 14.14/√2
= 9.998 Å (approx.)
Step 3: Determine the Distance between the Centres of Two C60 Molecules
Since each C60 molecule is centred at a lattice point, the distance between the centres of two C60 molecules can be calculated as the distance between two adjacent lattice points, which we calculated in Step 2.
Therefore, the distance between the centres of two C60 molecules is approximately 9.998 Å.
Step 4: Compare the Distances from Steps 2 and 3
Comparing the distances calculated in Steps 2 and 3, we see that the distance between the centres of two C60 molecules is the smallest distance.
Therefore, the smallest distance between the centres of two C60 molecules in Fullerene is approximately 9.998 Å.
Community Answer
Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with ...
√2a = 4r
r = 10
r = 10
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Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is?
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Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is?.
Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Fullerene crystallizes in an fcc unit cell (edge length =14.14A) with one c60 centred at each lattice point. The smallest distance between the centres of two c60 molecules is?.
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