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A bacterial population in the log-phase grows from 4 × 106 cells to 8.64 × 106 cells in 20 minutes. The doubling time of the bacterium is ____ minutes (round off to 1 decimal place)
    Correct answer is '17.9 to 18.1'. Can you explain this answer?
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    A bacterial population in the log-phase grows from 4 × 106 cells...
    A bacterial population in the log-phase grows from 4 to 32 in one hour.
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    A bacterial population in the log-phase grows from 4 × 106 cells to 8.64 × 106 cells in 20 minutes. The doubling time of the bacterium is ____ minutes (round off to 1 decimal place)Correct answer is '17.9 to 18.1'. Can you explain this answer?
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    A bacterial population in the log-phase grows from 4 × 106 cells to 8.64 × 106 cells in 20 minutes. The doubling time of the bacterium is ____ minutes (round off to 1 decimal place)Correct answer is '17.9 to 18.1'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A bacterial population in the log-phase grows from 4 × 106 cells to 8.64 × 106 cells in 20 minutes. The doubling time of the bacterium is ____ minutes (round off to 1 decimal place)Correct answer is '17.9 to 18.1'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bacterial population in the log-phase grows from 4 × 106 cells to 8.64 × 106 cells in 20 minutes. The doubling time of the bacterium is ____ minutes (round off to 1 decimal place)Correct answer is '17.9 to 18.1'. Can you explain this answer?.
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