the ratio of minimum wavelength of Lyman and balmer series will be ?

Question

Answer

by using formula let wavelength. = ¥1/¥ = R(  1/n(1)²   -    1/n(2)²    )here n(2) in both case is ∞and n(1) is shell where electron reach in Lyman n(1) = 1 1/¥(L) = R( 1/1²  - 1/∞² )1/¥ (L) = R .....{1}in blamer  n(1) = 21/¥(B) = R ( 1/2² - 1/∞² )1/¥(B) = R (1/4).....{2}equation {2}÷{1}¥(L) / ¥(B) = (R/4) ÷(R)ratio of minimum wavelength of Lyman to Balmer is       1:4

Answer

sorry wave number will be 4:1 but wavelength will be 1:4.

Answer

0.25

Answer

I think it's 4:1 as it will be 1/l^2÷1/b^2 when rydberg constant gets cancel out and shortest wavelength will be infinity (=0) and l=1 and b=2.

Answer

5/27since

Answer

Ratio of Minimum Wavelength of Lyman and Balmer Series
The ratio of the minimum wavelengths of the Lyman and Balmer series can be calculated based on the formula for the wavelengths of spectral lines emitted by hydrogen atoms. The Lyman series corresponds to transitions ending in the ground state (n=1) while the Balmer series corresponds to transitions ending in the first excited state (n=2).

Calculating the Wavelengths
1. The formula for calculating the wavelength of a spectral line emitted by hydrogen is given by the Rydberg formula:
$\frac {1}{\lambda} = R (\frac{1}{n_1^2} - \frac{1}{n_2^2})$
where R is the Rydberg constant, n1 is the initial energy level, and n2 is the final energy level.
2. For the Lyman series, n1 = 2 and n2 = 1. Substituting these values into the formula gives the minimum wavelength for the Lyman series.
3. For the Balmer series, n1 = 3 and n2 = 2. Substituting these values into the formula gives the minimum wavelength for the Balmer series.

Calculating the Ratio
4. By dividing the minimum wavelength of the Lyman series by the minimum wavelength of the Balmer series, you can find the ratio between the two series.
5. Simplifying this ratio will give you a numerical value that represents the relationship between the minimum wavelengths of the Lyman and Balmer series.
In conclusion, the ratio of the minimum wavelengths of the Lyman and Balmer series can be calculated using the Rydberg formula for hydrogen spectral lines. This ratio provides insight into the energy levels and transitions of hydrogen atoms, helping us understand the behavior of atomic spectra.

Similar Class 11 Doubts

If the shortest wavelength of lyman series of H atom is x, then the wavelength of first line of balmer series of H atom will be?

The ratio of difference in wavelengths of 1st and 2nd lines of Lyman series in H-like atom to difference in wavelength for 2nd and 3rd lines of same series is

In Lyman series, shortest wavelength of H-atom appears at x m, then longest wavelength in Balmer series of He+ appear at

In H-atom, electron transits from 6th orbit to 2nd orbit in multi step. Then total spectral lines (without Balmer series) will be :- 1) 6 2)10 3)4 4) 0 Ans~6 How?

Among lyman,balmer,paschen and brackett series in hydrogen atomic spectra which has higher energy?

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test Series

English Class 11

Chemistry Practice Tests: CUET Preparation

CUET Mock Test: Humanities Subjects 2025

Top Courses for Class 11

Top Courses for Class 11

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams