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Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Direction (Q. Nos. 18-27) This section contains 5 paragraphs, each describing theory, experiments, data, etc. Ten questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).Passage IA 22.4 L flask contains 0.76 mm of O3 at 298 K. It reacts with oxygen atoms asO + O3 2O2, k = 1.5 x 107 L mol-1 s-1 at the rate of 0.15 mol L-1 s-1.Q.What is the concentration of oxygen atoms needed to maintain this rate?a)2.45x 10-4 mol L-1b)4,087 x 10-5 mol-1c)0.30 mol-1d)None of theseCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.