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A shopkeeper only accepts packages in the form of a right circular cylinder. If sum of the height and the diameter of the base does not exceeds 20 cm. then the height (in cm) of a package of maximum volume that would be accepted will be? 
  • a)
    10/3 
  • b)
    20/3 
  • c)
    20 
  • d)
    30 
Correct answer is option 'B'. Can you explain this answer?
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To find the height of the package with maximum volume, we need to analyze the given conditions and use mathematical optimization techniques.

Let's break down the problem step by step:

1. Understanding the Constraints:
- The package should be in the form of a right circular cylinder.
- The sum of the height and the diameter of the base should not exceed 20 cm.

2. Formulating the Problem:
- We need to find the height of the cylinder that will result in the maximum volume.
- Let's assume the height of the cylinder as 'h' and the diameter of the base as 'd'.
- The volume of a cylinder is given by V = πr²h, where r is the radius of the base.

3. Expressing Constraints in Terms of Variables:
- The sum of the height and the diameter of the base should not exceed 20 cm.
- Since the diameter is twice the radius, we can express this constraint as h + 2r ≤ 20.

4. Relating Variables:
- We can relate the height 'h' and the radius 'r' using the formula for the diameter of the base: d = 2r.
- Rearranging this equation, we get r = d/2.

5. Expressing Volume in Terms of Single Variable:
- Substituting the value of r in the volume equation, we get V = π(d/2)²h.
- Simplifying further, V = (π/4)d²h.

6. Finding the Maximum Volume:
- To find the maximum volume, we need to maximize the expression (π/4)d²h.
- Since d is twice the radius, we can express it as d = 2r = 2(h/2) = h.
- Substituting this value, the expression becomes V = (π/4)h²h = (π/4)h³.
- Now, we need to find the value of h that maximizes this expression.

7. Applying Optimization Techniques:
- To find the maximum value of a function, we differentiate it with respect to the variable and equate it to zero.
- Differentiating V = (π/4)h³ with respect to h, we get dV/dh = (3π/4)h².
- Setting dV/dh = 0, we find h² = 0, which implies h = 0.

8. Analyzing the Result:
- Since the height cannot be zero, we need to consider the boundary conditions.
- The sum of the height and the diameter of the base should not exceed 20 cm.
- Let's consider the case when the sum is exactly 20 cm: h + d = 20.
- Substituting d = h, we get h + h = 20, which implies 2h = 20.
- Solving this equation, we find h = 10 cm.

Therefore, the height of the package with maximum volume that will be accepted by the shopkeeper is 10 cm, which corresponds to option B) 20/3 cm.
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A shopkeeper only accepts packages in the form of a right circular cylinder. If sum of the height and the diameter of the base does not exceeds 20 cm. then the height (in cm) of a package of maximum volume that would be accepted will be?a)10/3b)20/3c)20d)30Correct answer is option 'B'. Can you explain this answer?
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A shopkeeper only accepts packages in the form of a right circular cylinder. If sum of the height and the diameter of the base does not exceeds 20 cm. then the height (in cm) of a package of maximum volume that would be accepted will be?a)10/3b)20/3c)20d)30Correct answer is option 'B'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about A shopkeeper only accepts packages in the form of a right circular cylinder. If sum of the height and the diameter of the base does not exceeds 20 cm. then the height (in cm) of a package of maximum volume that would be accepted will be?a)10/3b)20/3c)20d)30Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shopkeeper only accepts packages in the form of a right circular cylinder. If sum of the height and the diameter of the base does not exceeds 20 cm. then the height (in cm) of a package of maximum volume that would be accepted will be?a)10/3b)20/3c)20d)30Correct answer is option 'B'. Can you explain this answer?.
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