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The sides of a right angled triangle are equal to three consecutive numbers expressed in centimeters. What can be the area of such a triangle ? 
  • a)
    6 cm² 
  • b)
    8 cm² 
  • c)
    10 cm² 
  • d)
    12 cm² 
Correct answer is option 'A'. Can you explain this answer?
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To solve this problem, let's assume that the three consecutive numbers are x, x+1, and x+2.

According to the Pythagorean theorem, the sum of the squares of the two shorter sides of a right-angled triangle is equal to the square of the hypotenuse. In this case, we have:

x^2 + (x+1)^2 = (x+2)^2

Expanding and simplifying this equation, we get:

x^2 + x^2 + 2x + 1 = x^2 + 4x + 4

Combining like terms, we have:

2x^2 + 2x + 1 = x^2 + 4x + 4

Subtracting x^2 and 4x from both sides, we get:

x^2 - 2x - 3 = 0

Factoring this quadratic equation, we get:

(x - 3)(x + 1) = 0

So, x = 3 or x = -1. Since we are dealing with lengths, we can ignore the negative solution. Therefore, x = 3.

Thus, the sides of the right-angled triangle are 3 cm, 4 cm, and 5 cm.

The area of a right-angled triangle is given by the formula: Area = (1/2) * base * height.

In this case, the base and height of the right-angled triangle are 3 cm and 4 cm, respectively.

Therefore, the area of the right-angled triangle is:

Area = (1/2) * 3 cm * 4 cm = 6 cm^2

So, the area of such a triangle can be 6 cm^2, which corresponds to option (a).
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The sides of a right angled triangle are equal to three consecutive numbers expressed in centimeters. What can be the area of such a triangle ?a)6 cm²b)8 cm²c)10 cm²d)12 cm²Correct answer is option 'A'. Can you explain this answer?
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