Ram aims to score an average of 85 percent marks in quarterly and half...
To solve this problem, let's break it down step by step:
Let's assume the total marks for the quarterly exam is Q and the total marks for the half-yearly exam is H.
According to the given information:
Ram's average in the quarterly exam is 5 percent less than his target. So, his average marks in the quarterly exam will be (85 - 5) = 80 percent of Q.
Ram's average in the half-yearly exam is 3 percent more than his target. So, his average marks in the half-yearly exam will be (85 + 3) = 88 percent of H.
Now, let's calculate the total marks obtained by Ram in both exams:
Total marks obtained in the quarterly exam = 80/100 * Q
Total marks obtained in the half-yearly exam = 88/100 * H
According to the given information, the difference between the total marks obtained in both exams is 48. So, we can write the following equation:
(88/100 * H) - (80/100 * Q) = 48
Now, let's simplify the equation:
88H/100 - 80Q/100 = 48
8H/100 - 8Q/100 = 48
8(H/100 - Q/100) = 48
H/100 - Q/100 = 48/8
H/100 - Q/100 = 6
Simplifying further, we get:
H - Q = 600
Since we are looking for the total marks aimed by Ram, we need to find the value of Q + H. From the equation above, we can substitute H - Q with 600:
Q + H = Q + (H - Q) = Q + 600
Now, let's substitute the value of Q + H in the equation we derived earlier:
Q + 600 = 600 + 600 = 1200
Therefore, the total marks aimed by Ram is 1200.
However, none of the provided options match the calculated answer. Therefore, it seems there is an error in the question or options as the calculated answer does not match any of the given options.
Ram aims to score an average of 85 percent marks in quarterly and half...
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